I am trying to add filter
as shown in the examples to my program:
val logFile = "/tmp/master.txt"
val sc = new JavaSparkContext("local[4]", "Twitter Analyzer", "/home/welcome/Downloads/spark-1.1.0/",Array("target/scala-2.10/Simple-assembly-0.1.0.jar"))
val twitterFeed = sc.textFile(logFile).cache()
while (iterator.hasNext) {
val value = iterator.next()
val numAs = twitterFeed.filter(line => line.contains(value))
numAs.saveAsTextFile("/tmp/output/positive/" + value)
}
I get the compilation error as follows:
[info] Compiling 1 Scala source to /home/siva/file1/target/scala-2.10/classes...
[error] /home/siva/file1/src/main/scala/com/chimpler/example/twitter/Tweet.scala:27: missing parameter type
[error] val numAs = twitterFeed.filter(line => line.contains(value))
[error] ^
[error] one error found
[error] (compile:compile) Compilation failed
[error] Total time: 5 s, completed 19 Sep, 2014 1:31:26 PM
any ideas?
As @groverboy advised in the comment you should really be using org.apache.spark.SparkContext instead. Spark Programming Guide's Initializing Spark is also clear on this.
import org.apache.spark._
val conf = new SparkConf()
.setMaster("local[4]")
.setAppName("Twitter Analyzer")
.setSparkHome("/home/welcome/Downloads/spark-1.1.0/")
.setJars(Seq("target/scala-2.10/Simple-assembly-0.1.0.jar"))
val sc = new SparkContext(conf)
The reason for this is the type inference in Scala that needs type context to infer the type of line
parameter.
val numAs = twitterFeed.filter(line => line.contains(value))
It's clearly of String
type, but using the Java version of SparkContext - JavaSparkContext - you simply lose the type information.
Provided you use SparkContext
the above line could be further simplified to:
val numAs = twitterFeed.filter(_.contains(value))
or even:
twitterFeed.filter(_ contains value)
All the goodies just SparkContext
away.
val numAs = twitterFeed.filter((i: String) => i.contains(value))
解决了这个问题。
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