PHP echo not printing

Question

Am facing a weird issue in my PHP coding...let me describe the purpose of my PHP code

1. Read Cell Value from excel and upload it in a MySQL table
2. Read EACH value from MySQL table and fetch data from an external source
3. Store the data in table fetched from external source
4. Echo the process is done
5. Echo a link to display the result

The code is perfectly working fine but when the Excel row size is big then Point 1,2,3 is working but 4,5 is not displaying

There is no error no warning...

Am just clueless why this issue is happening

Am attaching the code snippet below:

<?php

error_reporting (E_ALL ^ E_NOTICE);

error_reporting (E_ALL ^ E_DEPRECATED);

error_reporting(0);

session_start();

require_once("index11.php");

require_once("simple_html_dom.php");

include('ganon.php');

ini_set('max_execution_time', 1200);






$val2 = $_SESSION['$val2'];




if($_SESSION['$val8'] == "mu")
{

if($_SESSION['$val2'] == "fr")

{

//echo "MU for FR";


$conn = mysql_connect("localhost", "root", "****");


if (!$conn) {
    echo "Unable to connect to DB: " . mysql_error();
    exit;
}

if (!mysql_select_db("DB")) {
    echo "Unable to select mydbname: " . mysql_error();
    exit;
}


$sql = "SELECT DISTINCT EANcode from test WHERE timestamp = DATE( NOW( ) ) and EAncode <> ''";



$result = mysql_query($sql);
$a = 0;

while ($row = mysql_fetch_assoc($result)) {

foreach ($row as $b) 

 { 
$ean = $b;

$url = "WWW.URL.COM" .$ean;

$html = file_get_html($url);


$link=$html->find('a[class=webtrekk]');

$link1 = $link[4] -> href;


$link2 = "WWW.URL.COM" .$link1;

$html = file_get_dom($link2);


$i = 0;

foreach($html('tr') as $rowdata) {
        $name = '';
        $test1 = '';

       foreach($rowdata('a[class="test1"]') as $d) {
            $name = $d('img', 0)->alt;

$name2 = mysql_real_escape_string($name);
$arr = explode("-", $name2, 2);
$name1 = $arr[0];


        }      

foreach($rowdata('td[class="test1"]') as $d) {
            foreach($d('span[class="test1"]') as $d2) {
                $test1 = $d2->getPlainText();
            }
        }      

if(!$test1 == "")
{
$i = $i + 1;

$now = new DateTime();

$dt = $now->format('Y-m-d H:i:s');

mysql_select_db("DB", $conn);

$sql = "INSERT INTO `DB`.`tab_fr` (`pos`, `ean`, `prod_url`, `prod_compttr`, `prod_test1`, `timestamp`) VALUES ('$i', '$ean','$link2','$name1','$test1', '$dt')";

mysql_query($sql) or die('Error, insert query failed' . mysql_error());




}
    }


}      

}
flush();
usleep(300000);
$msg = "Query op Test.fr succesvol afgerond"; 
echo $msg ."<br/>" ;

}


if($_SESSION['$val2'] == "fr")
{
$v2 = "Test.fr,";
}
else
{
$v2 = "";
}


if($_SESSION['$val2'] == "fr")
{

echo "<a href=10d2.php>cLICK HERE ".$v2."</a>" ."<br/>";

}
}

?>

This is happening because of the timeout issue encountered in the code can anybody help me how to continue coding after time out.

Answer 1

When a large number of data is being processed then it may cause a situation equivalent to infinite loop. You see data insertion is success in database but it is not finished. So you have to find a trick to avoid this infinite looping execution.

Hints: break the entire loop into 3 or two.