Comma separated values into select query

Question

I'm new to PHP and i'm trying to create a small app for my work but i'm stuck few days now because i have a problem and i can't find a solution.

I have 2 tables first jobs_userac that contains 3 fields:

id, user, jobsassigned

and the second jobs_data that contains 5 fields:

id, job_type, description, comments, client_name

Every row in jobs_data contain a task

1 - Offset  - Blablablabla - Blablablabla - Chris
2 - Plotter - Blablablabla - Blablablabla - Nick
3 - Design  - Blablablabla - Blablablabla - John

For every user i have one row in jobs_userac that contains the user id, username, and the assignes jobs in one field comma separated.

1 - Chris - 1,2
2 - Peter - 2,4,5
2 - Maria - 4

Every time a user is connected i store the user id into a variable $user. I want to create a query like this

$result = mysqli_query($con,"SELECT * FROM jobs_data");

But i want to check if the connected user has a row in jobs_userac for example if the connected user is Chris to show him only the jobs from task_data where the job_type is 1 or 2 and if Maria is connected to show her the rows from jobs_data where the job_type=4. I want to add the WHERE clause into my query and if the user has more that one joobs assigned in jobs_userac--> jobsassigned to add the OR clause.

For user Maria

$result = mysqli_query($con,"SELECT * FROM jobs_data WHERE job_type=4");

For user Chris

$result = mysqli_query($con,"SELECT * FROM jobs_data WHERE job_type=1 OR job_type=2");

For user Peter

$result = mysqli_query($con,"SELECT * FROM jobs_data WHERE job_type=2 OR job_type=4 OR job_type=5");

Any help will be very much appreciated.

Answer 1

Your data structure is not ideal - your jobs_userac should have one row per user<->job link.

But you can work with what you have:

SELECT * FROM `jobs_data` WHERE FIND_IN_SET(`job_type`, "2,4,5")

Answer 2

I am not sure for the column of user at jobs_userac whether it is storing a userId or username

here it is assuming that user are storing username or if not then kindly replace the username with the user id.

select * from jobs_data where IN(select jobsassigned 
                                 from jobs_userac 
                                 where user = 'Perter');

I hope this helps you.

Answer 3

Additionally store jobsassigned of each user on connection in $jobsassigned Now you can do the following query:

$queryString = 'select * from jobs_data where id IN ('.$jobsassigned.')';

By the way... it is better to add an extra table where you store youre relations between user and jobs

jobs

1 - Offset  - Blablablabla - Blablablabla - Chris
2 - Plotter - Blablablabla - Blablablabla - Nick
3 - Design  - Blablablabla - Blablablabla - John

users

1 - Chris
2 - Peter
3 - Maria

user_job

1 - 1
1 - 2
2 - 2
2 - 4
2 - 5
3 - 4

Answer 4

As others noted your current schema is sub-optimal and generally speaking not the best way to exploit a relation data base however you can use your current structure in a query with the somewhat clumsy :

"SELECT * FROM JOBS_DATE WHERE id = '2' or id like '2,%' or id like '%,2,%' or id like '%,2'"

You need all thee likes as you have to copy with "2,5,7", "1,2,3" and "1,2" plus the equal for plain "2"

Answer 5

First you have to get the job type assign to the link user:

$result = mysqli_query($con,"SELECT * FROM jobs_useracc where id=".$user);
$row = mysql_fetch_array($result);
$job_types=$row['jobassigned'];
$result = mysqli_query($con,"SELECT * FROM jobs_data where id IN (".$job_types.")");

Answer 6

If each job is only every associated with one user, the id of that user should be stored against the job. so your tables should be id, user and id, job_type, description, comments, client_name, user_id . Then you can get the jobs for Chris by doing SELECT * FROM jobs_data WHERE user_id = 1 . This is a normal pattern for where you have many entries in one table associated with one entry in another.

Answer 7

You are referring to job_type instead of id .

You should follow :

$result = mysqli_query($con,"SELECT * FROM jobs_data WHERE id=2 OR id=4 OR id=5");

And same for others ie use id at place of job_type .