Hibernate, Spring, Struts2: Open Session in View pattern

Question

I'm working on a project using Hibernate for persisting and Struts2 for the view pattern. my configuration files are:

web.xml

 <web-app>
     //......
     //.....
     <filter>
        <filter-name>struts2</filter-name>
        <filter-class>
          org.apache.struts2.dispatcher.ng.filter.StrutsPrepareAndExecuteFilter
        </filter-class>
      </filter>
      <filter-mapping>
        <filter-name>struts2</filter-name>
        <url-pattern>/*</url-pattern>
      </filter-mapping>

      <!-- The defintion of the root Spring Container shared by all Servlets and Filters -->
      <context-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>classpath:applicationContext.xml</param-value>
      </context-param>
      <!-- Creates the spring Container shared by all servlet and filters -->
      <listener>
        <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
      </listener>

       <filter> <!-- Get spring to keep the session open for the whole request, so hibernate's lazy loads work -->
        <filter-name>openSessionInViewFilter</filter-name>
        <filter-class>org.springframework.orm.hibernate3.support.OpenSessionInViewFilter</filter-class>
      </filter>
      <filter-mapping>
        <filter-name>openSessionInViewFilter</filter-name>
        <url-pattern>/*</url-pattern> 
      </filter-mapping>
    </web-app>

---

applicationContext.xml

<?xml version="1.0" encoding="UTF-8"?>
<beans >
//.......
<bean id="dataSource" class="org.springframework.jdbc.datasource.DriverManagerDataSource">
        <property name="driverClassName" value="com.mysql.jdbc.Driver"></property>
        <property name="url" value="jdbc:mysql://localhost:3306/DB_TEST"></property>
        <property name="username" value="root"></property>
        <property name="password" value=""></property>
    </bean>

    <bean id="persistenceUnitManager" class="org.springframework.orm.jpa.persistenceunit.DefaultPersistenceUnitManager">
        <property name="persistenceXmlLocations">
            <list>
                <value>classpath*:META-INF/persistence.xml</value>
            </list>
        </property>
        <property name="defaultDataSource" ref="dataSource"></property>
    </bean>

    <bean id="entityManagerFactory" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
        <property name="persistenceUnitManager" ref="persistenceUnitManager"></property>
    </bean>

    <bean id="transactionManager" class="org.springframework.orm.jpa.JpaTransactionManager">
        <property name="entityManagerFactory" ref="entityManagerFactory"></property>
    </bean>

    <tx:annotation-driven transaction-manager="transactionManager" />
    <context:annotation-config></context:annotation-config>
</beans>

---

My probleme is I can't keep Hibernate session open in the view pattern of Struts2, means when I try to load some data that are not already initialized with Hibernate (like collections for example) i get the org.hibernate.LazyInitializationException , so after doing some research I found that I must add this scope in web.xml to keep the session open in the view pattern.

Scope

<filter> <!-- Get spring to keep the session open for the whole request, so hibernate's lazy loads work -->
    <filter-name>openSessionInViewFilter</filter-name>
    <filter-class>org.springframework.orm.hibernate3.support.OpenSessionInViewFilter</filter-class>
  </filter>
  <filter-mapping>
    <filter-name>openSessionInViewFilter</filter-name>
    <url-pattern>/*</url-pattern> 
  </filter-mapping>

---

But even with this I still have the same problem, so can anyone tell me what i'm doing wrong.

Answer 1

The order of filter chain is important. In your case the session should be opened before struts is executing actions and closed after that. The last thing is done by spring via managing Hibernate session. So, reorder filters and allow struts2 dispatcher accept requests from the first filter.

   <filter> <!-- Get spring to keep the session open for the whole request, so hibernate's lazy loads work -->
    <filter-name>openSessionInViewFilter</filter-name>
    <filter-class>org.springframework.orm.hibernate3.support.OpenSessionInViewFilter</filter-class>
  </filter>
  <filter-mapping>
    <filter-name>openSessionInViewFilter</filter-name>
    <url-pattern>/*</url-pattern> 
  </filter-mapping>

 <filter>
    <filter-name>struts2</filter-name>
    <filter-class>
      org.apache.struts2.dispatcher.ng.filter.StrutsPrepareAndExecuteFilter
    </filter-class>
  </filter>
  <filter-mapping>
    <filter-name>struts2</filter-name>
    <url-pattern>/*</url-pattern>
    <dispatcher>REQUEST</dispatcher>
    <dispatcher>FORWARD</dispatcher>
  </filter-mapping>

Answer 2

I've had similar problem some time ago, and to resolve this I used hibernate.enable_lazy_load_no_trans property instead of OpenSessionInView pattern. More informations about LazyInitializationException you can find here or here