I have 3 folders:
Each folder has its own start.bat (Folder1/Start.bat,etc..) I want to make a file, in the folder where the files are listed The file will open and run each .bat file in a separate window/command prompt So Folder1's bat file makes a new window and loads Then folder2. They wont all open in one window.
How would I do this? I got this:
cd C:\Users\Jackson\Desktop\MAIN FOLDER\Folder1
java -Xmx512M Start.bat
Even better would be if I could run multiple jars in there own windows with 1 .bat Like if I had
And I open each one in a seperate window (minecraft console stuff...)
If I'm confusing please tell me if you need me to explain it better. I prefer using the jar files directly instead of opening the bat files.
Use the START
command with the /B option to suppress the new windows. eg NB the double quotes are technically an optional window title but it's better to provide them.
START /B "" Java.exe blabla2.jar
START /B "" Java.exe blabal2.jar
...
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