Just out of curiosity, anyone know why
echo date("F", strToTime("$day-02-$year"));
would print out March, originally I thought it was a common off by one error but
echo date("F", strToTime("$day-01-$year"));
prints out January and
echo date("F", strToTime("$day-03-$year"));
prints out march, so I am unsure of what is actually going on here???
any ideas
You run this script today, so $day=30;
?
So, if you try to get the 30th day of February, it returns you the 2nd day of March - or March 1st in leap years. Obviously because February doesn't have enough days...
$day = 30;
$year = 2014;
echo date("r", strToTime("$day-02-$year"));
Output:
Sun, 02 Mar 2014 00:00:00 +0100
It's not a bug, it's a feature.
My problem was defaulting the day as a "j" i just made the default 01 if there was no day set and it works now,
I have a calendar that I was going from month to month with simple buttons and the day was never set in my conditional statement I had that if the day was not set that the default was a lowercase j as soon as I changed that it responded with the correct name, So the answer to this question is to ensure that the default day is set to 1 if there is not going to be a day present such as when you are going from month to month
<?php
if (isSet($_GET['day'])) {
$day = $_GET['day'];
} else {
$day = date("01");
}
if (isSet($_GET['month'])) {
$month = $_GET['month'];
} else {
$month = date("n");
}
if (isSet($_GET['year'])){
$year = $_GET['year'];
} else {
$year = date("Y");
}
//calendar variable
$currentTimeStamp = strToTime("$day-$month-$year");
//get current month name
$monthName = date("F", $currentTimeStamp);
//get how many days are in the current month
$numDays = date("t", $currentTimeStamp);
//counter for calendar cells in loop
$counter = 0;
?>
like so!
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