Server did not recognize the value of HTTP Header SOAPAction:

Question

I'm trying to call a SOAP webservice using SAAJ for this WSDL. I submitted the request for this WSDL here http://www.webservicex.net/ws/WSDetails.aspx?WSID=64 and it generated the following SOAP requests..

<?xml version="1.0" encoding="utf-8"?>
<soap:Envelope xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/">
  <soap:Body>
    <GetGeoIP xmlns="http://www.webservicex.net/">
      <IPAddress>string</IPAddress>
    </GetGeoIP>
  </soap:Body>
</soap:Envelope>

Using SAAJ I generated the same SOAP requests and submitted it but get this error - Server did not recognize the value of HTTP Header SOAPAction: .

<SOAP-ENV:Envelope xmlns:SOAP-ENV="http://schemas.xmlsoap.org/soap/envelope/" xmlns:xsd="http://www.w3.org/2001/XMLSchema"><SOAP-ENV:Header/>
<SOAP-ENV:Body>
<GetGeoIP xmlns="http://www.webservicex.net/">
<IPAddress>SUNW</IPAddress>
</GetGeoIP>
</SOAP-ENV:Body>
</SOAP-ENV:Envelope>

Java Code:

package newpackage;

import javax.xml.namespace.QName;
import javax.xml.soap.*;

public class SOAPClientSAAJ {

    public static void main(String args[]) throws Exception {
        // Create SOAP Connection
        SOAPConnectionFactory soapConnectionFactory = SOAPConnectionFactory.newInstance();
        SOAPConnection soapConnection = soapConnectionFactory.createConnection();

        // Send SOAP Message to SOAP Server
        String url = "http://www.webservicex.net/geoipservice.asmx";
        SOAPMessage soapResponse = soapConnection.call(createSOAPRequest(), url);

        // print SOAP Response
        System.out.print("Response SOAP Message:");
        soapResponse.writeTo(System.out);

        soapConnection.close();
    }

    private static SOAPMessage createSOAPRequest() throws Exception {
        MessageFactory messageFactory = MessageFactory.newInstance();
        SOAPMessage soapMessage = messageFactory.createMessage();
        SOAPPart soapPart = soapMessage.getSOAPPart();

        String serverURI = "http://www.w3.org/2001/XMLSchema";

        // SOAP Envelope
        SOAPEnvelope envelope = soapPart.getEnvelope();
        envelope.addNamespaceDeclaration("xsd", serverURI);

        SOAPBody body = soapMessage.getSOAPBody();
        QName bodyName = new QName("http://www.webservicex.net/", "GetGeoIP" );
        SOAPBodyElement bodyElement = body.addBodyElement(bodyName);
        QName name = new QName("IPAddress");
        SOAPElement symbol = bodyElement.addChildElement(name);
        symbol.addTextNode("SUNW");
        soapMessage.saveChanges();

        /* Print the request message */
        System.out.print("Request SOAP Message:");
        soapMessage.writeTo(System.out);
        System.out.println();

        return soapMessage;
    }

}

Answer 1

Add

    MimeHeaders headers = soapMessage.getMimeHeaders();
    headers.addHeader("SOAPAction", "http://www.webservicex.net/" + "GetGeoIP");

Answer 2

If you are using Marshelling and Unmarsheling, Just implement WebseviceMessageCallback interface like:

public class SOAPConnector extends WebServiceGatewaySupport
{
    public Object callWebService( String url, Object request )
    {
        return getWebServiceTemplate().marshalSendAndReceive( url, request,  
webServiceMessage -> {
            (( SoapMessage )webServiceMessage).setSoapAction( 
"https://www.w3schools.com/xml/CelsiusToFahrenheit" );
        } );
    }
}

Otherwise proceed with: https://stackoverflow.com/a/26253141/6097074