fgets adds \0 or \n at the end of the input?

Question

I've some doubts about fgets. From what I know, it adds "\n" at the end of the string, and not "\0". So if I write this code:

fgets(buff,2,stdin);
printf("%s",buff);

So fgets reads two characters, I give as input "y", so buff should be "y\n". I'd expect printf to print y and add a line, while it prints "y" without adding a line. Can you explain why?

Answer 1

char * fgets ( char * str, int num, FILE * stream );

Reads characters from input stream and stores them as a C string into str until (num-1) characters have been read or either a newline or the end-of-file is reached, whichever happens first.

A newline character makes fgets stop reading, but it is considered a valid character by the function and included in the string copied to str.

A terminating null character ('\\0') is automatically appended after the characters copied to str.

Answer 2

It must terminate the string, so yes it will always add '\\0' at the end. However, fgets might not always add the newline, if it doesn't fit. I recommend this reference page for fgets .

Answer 3

According to man page it clearly given :

 char *fgets(char *s, int size, FILE *stream);

fgets() reads in at most one less than size characters from stream and stores them into the buffer pointed to by s. Reading stops after an EOF or a newline. If a newline is read, it is stored into the buffer. A '\\0' is stored after the last character in the buffer.

Answer 4

fgets() adds \0 at the end but it reads the string with \n if it exists in the file

i have such thing after reading string: "guitar\n\0\U00000004\xd5..."

my file had string with word "guitar" and \n after it so, as u see it read the word with "\n" and added "\0" to the string