Use of function execlp() in C

Question

I'm trying to use the function execlp() to make a child processes run a specific code that I wrote, but I don't understand how the path works.

NOTE: I use export PATH=$PATH:. in the terminal so I don't need to type /.ProgName every time.

The first program is:

#include <stdio.h>
#include <stdlib.h>
#include <sys/types.h>
#include <unistd.h>
main() {

    pid_t childpid; 
    int i;
    int nprocess = 3;
    for (i = 0; i < nprocess; ++i) {
     if ((childpid = fork()) < 0) {
         perror("fork:");
         exit(1);
     } 
     if (childpid==0){ 
        printf("I'm the son with ID= %ld\n",(long)getpid());
        char *path = "exectest";
        if ((execl(path,"0",NULL))<0) printf("\n error exec \n");
    } 
      else 
        printf("I'm the father with ID= %ld",(long)getpid());
    }

}

The second program to be called by the execlp is :

#include <stdio.h>
#include <stdlib.h>
#include <sys/types.h>
#include <unistd.h>
#include <time.h>


void main(){


        printf("\n I'm using exec \n");

}

Both programs are in the same directory. The second program is named "exectest" but when I launch the first, I get the error message.

Answer 1

由于第一个程序启动可执行文件exectest ，因此应编译第二个文件exectest.c并获取名为exectest可执行文件。