I am learning C++ now, very new. I am trying to make a very simple program which show a multiplication tables, when program runs user enter a first number and then a 2nd one and program shows the table. But the problem is that when I press any key on keyboard the program exits. And I want that at this point program repeats itself and asks the user for the first number. My code is here:
#include <iostream>
#include <conio.h>
using namespace std;
int main(int argc,char**argv){
int value1;
int limit;
int result1=1;
int result2;
bool runing=false;
printf("Welcome \n");
cout << "Please enter 1st value: " << flush;
cin >> value1;
cout << "Please enter a limit value: "<< flush;
cin >> limit;
cout<< "Result is: \n";
while(result1<=limit){
result2=result1*value1;
printf("%d x %d = %d\n",value1,result1,result2);
result1++;
}
return 0;
}
To do what you want, you just need another while loop that wraps everything after printing welcome. Like so:
#include <iostream>
#include <conio.h>
using namespace std;
int main(int argc,char**argv){
int value1;
int limit;
int result2;
bool runing=false;
printf("Welcome \n");
//I don't know in which conditions you want to quit the program.
//You could also use for() instead, to run this piece of code a certain number of times.
while(true){
int result1=1;
cout << "Please enter 1st value: " << flush;
cin >> value1;
cout << "Please enter a limit value: "<< flush;
cin >> limit;
cout<< "Result is: \n";
while(result1<=limit){
result2=result1*value1;
printf("%d x %d = %d\n",value1,result1,result2);
result1++;
}
}
return 0;
}
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