R: how can mapply take data.frame as a whole

Question

Say I have a data.frame and I want to subset this data by different filter and get a list of them, so I tried this:

df <- data.frame(A=c(1,2,3), B=c(7,8,9))
filter_lst <- list(c(1,2), c(2,3))
filter_by_range <- function(df, filter) {
  with(df, {df[A >= filter[1] &
               A < filter[2], ]})
}
mapply(filter_by_range, df, filter_lst)

But it shows error:

Error in eval(substitute(expr), data, enclos = parent.frame()) : 
  numeric 'envir' arg not of length one
Called from: with.default(df, {
    df[A >= filter[1] & A < filter[2], ]
})

I guess it's because df is taken as a list for mapply , how can mapply take df as a whole or any other better approaches to do this job?

Answer 1

As described in comments above:

 mapply(filter_by_range, filter=filter_lst, MoreArgs=list(df))
  [,1] [,2]
A 1    2   
B 7    8   

Notice that it was returned as a matrix because the default is SIMPLIFY=TRUE. If you wanted it as a list:

> mapply(filter_by_range, filter=filter_lst, MoreArgs=list(df), SIMPLIFY=FALSE)
[[1]]
  A B
1 1 7

[[2]]
  A B
2 2 8