sort using struct and pointers

Question

I am new to structs and pointer. Trying to learn them.Tried a simple sorting function with struct and pointer and but having some issues. Can some one help me understand them?

#include<stdio.h>
#include <stdlib.h>

int*
    sorting (int* arg)
    {

    int temp=0,j,i;
        for(i=1;i<5;i++)
        {
            for(j=0;j<5-i;j++)
            {
                if(arg[j] >arg[j+1])
                {
                    temp=arg[j];
                    arg[j]=arg[j+1];
                    arg[j+1]=temp;
                }
            }
        }
    return arg;
    }

int main(){

    int i;
    int n =5;
    int *result_;

    int *sorting_1_arg = malloc(n * sizeof *sorting_1_arg);

    printf("Sort\n "); 
    printf("Enter 5 elements to sort: ");       

    for (i =0; i <n; i++){
    scanf("%d", &sorting_1_arg[i]);
    }

    result_4 = sorting(sorting_1_arg);
    printf ("Sorted List recieved from Server ");

    for (i =0; i <n; i++){
    printf("%d",sorting_1_arg[i]);
    }
  return 0;
   }

When I run this code:

In function 'int main()':
[Error] invalid conversion from 'void*' to 'int*' [-fpermissive]

Answer 1

The programs seems fine to me. Except that there is an undeclared variable on line 39:

result_4 = sorting(sorting_1_arg);

Correct it to

result_ = sorting(sorting_1_arg);

The program runs fine. Just add a "\\n" for new lines to make it look better.

The site in here gives you a good introduction to structures and pointers.