string(150) "
SELECT *
FROM (
SELECT *, @row := @row +1 AS rownum
FROM (SELECT @row :=0) r, `coordinates`
WHERE fid='3'
) ranked
HAVING rownum % FLOOR(@row/20) = 1
"
$result = mysqli_query($link, $sql);
Connect Error: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ' FROM (SELECT *, @row := @row +1 AS rownum FROM (SELECT @row :=0) r, `coordina' at line 1
The first line is a var_dump of my $sql
variable, but the sql works just fine from command line. It reports an error when using the PHP.
Why is this, and how can I fix it?
This is just so weird, sorry that I do not know what the issue is but the $sql that is not commented out does not work and has string (150), but the $sql that is commented out works and is string (147), the editor is coda 2 on mac, and there are no spaces between "ranked" and "HAVING"
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