How to hidden the output of Linux command launched from shell_exec()

Question

Hi guys this is my code

<?php
  $res = shell_exec('curl  http://www.example.com');

I launched it from the terminal using this command

php script.php

and this is the output:

% Total    % Received % Xferd  Average Speed   Time    Time     Time  Current
Dload  Upload   Total   Spent    Left  Speed
100  1270  100  1270    0     0   5515      0 --:--:-- --:--:-- --:--:-- 11545

I don't want to see nothing how can i do??

Answer 1

You are seeing that output because curl outputs its current progress to STDERR.

You could solve this with a redirection if you want to ignore it:

$res = shell_exec('curl  http://www.example.com 2>/dev/null');

Or, in the shell level:

$ php script.php 2>/dev/null

Answer 2

You can use output buffering

ob_start();
$res = shell_exec('curl  http://www.example.com');
ob_end_clean();