One-Liner with Return Statement

Question

Is there a way to write the JavaScript code below as a one-liner?

this.isContactPage = (window.location.pathname === '/contact');
if (!this.isContactPage) return false;

The method continues on if this.isContactPage is true.

The property this.isContactPage is needed in other places in the script.

Answer 1

return !(this.isContactPage = (window.location.pathname === '/contact'));

Another example:

console.log(window.prop); // undefined
console.log(!(window.prop = true) || undefined); // undefined
console.log(!(window.prop = true)); // false
console.log(window.prop); // true

Answer 2

It'll be fairly dense and "obscured" code, but you can inline assignments in conditionals:

if ( !this.isContactPage = ( window.location.pathname == '/contact' ) ) return false;

This will only return the function if this.isContactPage is assigned the value false otherwise the function is not returned and continues on execution, as opposed to:

return ( this.isContactPage = ( window.location.pathname == '/contact' ) );

Which will return true or false immediately.

Answer 3

return !this.isContactPage = (window.location.pathname === '/contact')

Answer 4

with this you will not have errors!

this.isContactPage = /contact/gi.test(window.location.pathname);
if (!this.isContactPage) return false;

or

return !(/contact/gi.test(window.location.pathname))

Answer 5

I have something makes your code as short as possible!

return !(this.isContactPage=location.pathname=='/contact')

1. You don't need "Window"
2. You don't need returning false or true directly through your code
3. You don't need ===, then change it to == The shortest way guys suggested has 88 letters and this suggestion has just 68 letter and is more readable and understandable!