Xml values from URL in android

Question

Below, xml file at " http://example.com/example.xml "

<xml>

<result>
    <name>abc name</name>                       
    <first>568</first>
    <second>458</second>
    <third>185</third>
    <forth>236</forth>
    <last>974</last>
</result>

<result>
    <name>def name</name>                       
    <first>214</first>
    <second>456</second>
    <third>457</third>
    <forth>754</forth>
    <last>746</last>
</result>

</xml>

i want get first, second, third, forth and last value for abc name. how i get values from xml URL?

Answer 1

You should try using DOM parser. You should try using DOM parser.

NodeList nList = doc.getElementsByTagName(“result”);

System.out.println("----------------------------");

for (int temp = 0; temp < nList.getLength(); temp++) {

    Node nNode = nList.item(temp);

    if (nNode.getNodeType() == Node.ELEMENT_NODE) {

        Element eElement = (Element) nNode;

        if( eElement.getElementsByTagName("firstname").item(0).getTextContent().equals(“abc”))
        {
           System.out.println(“first” + eElement.getElementsByTagName(“first”).item(0).getTextContent());
           System.out.println(“second” + eElement.getElementsByTagName("nickname").item(0).getTextContent());
          //And so on           
         }

    }
}

Answer 2

These links provide some example and detail:

http://www.sitepoint.com/learning-to-parse-xml-data-in-your-android-app/ http://www.androidpeople.com/android-xml-parsing-tutorial-%E2%80%93-using-domparser http://www.ibm.com/developerworks/opensource/library/x-android/ http://www.anddev.org/parsing_xml_from_the_net_-_using_the_saxparser-t353.html

I hope this help you.