Open With Dialogue needed from DataGridView C#

Question

I have a Windows form in which I have a DataGridView that displays the list of files in a location. I have created a ContextMenu that will drop down on right click on a file name. Options in the menu are "Copy", "Open With" etc.

When I click "open With" in the menu I need to get the "Open With" dialogue box as in Windows and then I should be able to select the application with which I can open the file with.

I am not sure how to get the "Open With" Dialogue box. Can someone please help me with this?

Thanks in Advance!!!

Answer 1

This is maybe what you are looking for, just change what needs to be changed to accommodate for your app.

Open file dialog and select a file using WPF controls and C#

Answer 2

Try this:

using System.Diagnostics;
//...

private void openWith_Click(object sender, System.EventArgs e)
{
    Stream myStream = null;
    OpenFileDialog openFileDialog1 = new OpenFileDialog();

    openFileDialog1.InitialDirectory = "c:\\" ;
    openFileDialog1.Filter = "application (*.exe)|*.exe" ;
    openFileDialog1.FilterIndex = 2 ;
    openFileDialog1.RestoreDirectory = true ;

  if(openFileDialog1.ShowDialog() == DialogResult.OK)
  {
    try
    {
      ProcessStartInfo pi = new ProcessStartInfo();
      pi.Arguments = Path.GetFileName(file);//the file that you want to open
      pi.UseShellExecute = true;
      pi.WorkingDirectory = Path.GetDirectoryName(file);
      pi.FileName = openDialog1.FileName;
      pi.Verb = "OPEN";
      Process.Start(pi);

    }
    catch (Exception ex)
    {
        MessageBox.Show("Error: Could not open the file with this program. Original error: " + ex.Message);
    }
  }
}

Answer 3

You can use ShellExecuteEx function.
Usage of the example is OpenWith("Path to File");

        [Serializable]
    public struct ShellExecuteInfo
    {
        public int Size;
        public uint Mask;
        public IntPtr hwnd;
        public string Verb;
        public string File;
        public string Parameters;
        public string Directory;
        public uint Show;
        public IntPtr InstApp;
        public IntPtr IDList;
        public string Class;
        public IntPtr hkeyClass;
        public uint HotKey;
        public IntPtr Icon;
        public IntPtr Monitor;
    }

    // Code For OpenWithDialog Box
    [DllImport("shell32.dll", SetLastError = true)]
    extern public static bool
           ShellExecuteEx(ref ShellExecuteInfo lpExecInfo);

    public const uint SW_NORMAL = 1;

    static void OpenWith(string file)
    {
        ShellExecuteInfo sei = new ShellExecuteInfo();
        sei.Size = Marshal.SizeOf(sei);
        sei.Verb = "openas";
        sei.File = file;
        sei.Show = SW_NORMAL;
        if (!ShellExecuteEx(ref sei))
            throw new System.ComponentModel.Win32Exception();
    }