Removing elements in an array using Lodash

Question

I have this array:

var fruits = ['Apple', 'Banana', 'Orange', 'Celery'];

And I use Lodash's remove like so:

_.remove(fruits, function (fruit) {
  return fruit === 'Apple' || 'Banana' || 'Orange';
})

The result is ['Apple', 'Banana', 'Orange', 'Celery'] , while I expected it to be ['Apple', 'Banana', 'Orange'] . Why is this so?

Answer 1

Because when fruit is "Celery" , you are testing:

"Celery" === 'Apple' || 'Banana' || 'Orange'

which evaluates to

false || true || true

which is true .

You can't use that syntax. Either do it the long way around:

_.remove(fruits, function (fruit) {
  return fruit === 'Apple' || fruit === 'Banana' || fruit === 'Orange'
});

or test for array membership:

_.remove(fruits, function (fruit) {
  return _.indexOf(['Apple', 'Banana', 'Orange'], fruit) !== -1
});

This is not limited to JavaScript, and is in fact a common mistake (eg this question )

Answer 2

You can use the method _.pull from lodash 2.0 and up

 var fruits = ['Apple', 'Banana', 'Orange', 'Celery']; _.pull(fruits, 'Apple', 'Banana', 'Orange'); // ['Celery'] document.write(fruits); 

 <script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.6.1/lodash.js"></script> 

Answer 3

The problem isn't with Lo-Dash; your problem is with your conditional within your callback function. This:

return fruit === 'Apple' || 'Banana' || 'Orange';

Is not correct. You need to actually compare fruit with each string:

return fruit === 'Apple' || fruit === 'Banana' || fruit === 'Orange';

Or , you can use another Lo-Dash function to make it a little more compact:

_.remove(fruits, function (fruit) {
  return _.contains(['Apple', 'Banana', 'Orange'], fruit);
})

Note: In the latest versions of Lo-Dash the _.contains function is deprecated. Please use _.includes

Answer 4

If you want to remove a set of items from another set, there are set operations intended specifically for that. Lodash has https://lodash.com/docs/4.17.2#difference which takes two array parameters A and B and will return another array which contains all of the elements of A which are not in B.

In your case, you could write

const fruits = ['Apple', 'Banana', 'Orange', 'Celery'];
const filteredFruits = _.difference(fruits, ['Apple', 'Banana', 'Orange']);

which will result in ['Celery'] .

Answer 5

Use an array of values that you'd like to compare against, and check for a returned index greater than -1. This indicates the value evaluated was found in the collection.

_.remove( fruits, function ( fruit ) {
  return _.indexOf( [ "Apple", "Banana", "Orange" ], fruit ) >= 0;
});

Alternatively you could use lo-dash's _.contains method to get a boolean response.

The problem with the approach you took was that you weren't comparing fruit against each one of those strings; instead, the only comparison taking place was fruit against "Apple" , after that you were coercing strings all on their own.

Non-empty strings coerce to true ( !!"Banana" ), and as such are truthy . Therefore, the following condition will always short-circuit at "Banana" (unless fruit strictly equals "Apple" ), returning true :

return fruit === "Apple" || 'Banana' || "Orange";