The title pretty much says it all. Does JavaScript guarantee a total order on objects when using the <
, >
, <=
and >=
operators?
I wrote some code just to check total ordering on some objects. The result is consistent with total ordering, but that doesn't prove anything:
function thereIsTotalOrder(items){
var one, other, theThird;
// warning: n^3 complexity follows
// If a <= b and b <= a then a = b (antisymmetry);
for(var i=0; i<items.length; i++){
for(var j=0; j<items.length; j++){
one = items[i];
other = items[j];
if((one <= other) && (other <= one) && (one != other)){
return false;
}
}
}
// If a <= b and b <= c then a <= c (transitivity)
for(var i=0; i<items.length; i++){
for(var j=0; j<items.length; j++){
for(var k=0; k<items.length; k++){
one = items[i];
other = items[j];
theThird = items[k];
if((one <= other) && (other <= theThird) && !(one <= theThird)) {
return false;
}
}
}
}
// a <= b or b <= a (totality).
for(var i=0; i<items.length; i++){
for(var j=0; j<items.length; j++){
one = items[i];
other = items[j];
if(!((one <= other) || (other <= one))) {
return false;
}
}
}
return true;
}
function a(){};
function b(){};
var c = "foo";
var d = "bar";
var e = "bar";
var f = function(){};
var g = {name : "bananas"};
console.log(thereIsTotalOrder([a, b, c, d, e, f, g])); // prints "true"
Depends on what objects we're considering. If we confine our attention to the class of numbers , then yes, the order will be total. As your example demonstrates, the same can be said of (at least some) strings . But totality doesn't seem to hold generally.
For instance, if you add var h = 5;
to your declarations and then add h
to your thereIsTotalOrder
call, you will get a false
. That's because in a state where h = 5
and c = 'foo'
, ( h
≤ c
∨ c
≤ h
) is false (which means that totality is not satisfied).
As you rightly noted, while the absence of a false value returned by thereIsTotalOrder
doesn't prove that all objects are totally ordered, the presence of a false
value does prove that the order (if defined) between all objects is not total.
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