adding negative statement to regex

Question

I am trying to check if a phone number like this exists in using regex.

(001) 33992292

So, I used

if(preg_match("/[0-9\(\)]+/", $row)){
     //is phone number
  }

But, the problem with this is that, strings containing numbers get passed as well, like foo134@yahoo.com , so how can I evaluate a phone number and exclude @ character is strings all together?

Answer 1

UDPATED /^(\\(\\d+\\))*\\s?(\\d+\\s*)+$/

you missed start string ^ sign and end string $ sign, what else your regex is wrong because 5545()4535 will also pass match

Answer 2

您需要在正则表达式中使用锚点 ，正确的语法是：

if(preg_match('~^\(\d{3}\) *\d{8}$~', $row)) { ... }

Answer 3

Telephone numbers are notorious for people to get wrong - and by people I mean programmers.

For example, these are all "common" ways of writing a phone number:

(001) 33992292
001 33992292
00133992292
001 3399 2292
(001) 3399-2292

A saner approach it to just remove everything that isn't a number and check the length:

$phonenumber = "(001) 33992292";
$phonenumber = preg_replace("/[^0-9,.]/", "", $phonenumber );

if (strlen($phonenumber) == 11) {
    // do thing
}