I am working on one enhancement in my application. This application is Spring Hibernate implementation.But the enhancement now I am working is Spring-JPA. Without disturbing the existing implementation I need to include JPA Below is my DBconfiguration class.
@Configuration
@EnableJpaRepositories(basePackages = {"packagename","package name" })
@EnableTransactionManagement
public class DataBaseConfiguration {
@Value("${postgres.driver}")
private String postgresDriver;
@Value("${postgres.url}")
private String postgresUrl;
@Value("${postgres.username}")
private String postgresUsername;
@Value("${postgres.password}")
private String postgresPassword;
@Value("${hibernate.dialect}")
private String hibernateDialect;
@Value("${hibernate.dialect.property}")
private String dialectProperty;
@Value("${hibernate.show-sql}")
private String hibernateShowSql;
@Value("${boolean.true}")
private String booleanTrue;
**\\ existing hibernate flow**
@Autowired
@Bean(name = "name")
public SessionFactory getSessionFactory(DataSource dataSource) {
LocalSessionFactoryBuilder sessionBuilder = new LocalSessionFactoryBuilder(
dataSource);
sessionBuilder.addAnnotatedClasses(entity.class);
sessionBuilder.setProperty(hibernateDialect, dialectProperty);
sessionBuilder.setProperty(postgresDriver, postgresUrl);
sessionBuilder.setProperty(hibernateShowSql, booleanTrue);
return sessionBuilder.buildSessionFactory();
}
**\\ existing hibernate flow**
@Bean(name = "name")
public DataSource getDataSource() {
BasicDataSource dataSource = new BasicDataSource();
dataSource.setDriverClassName(postgresDriver);
dataSource.setUrl(postgresUrl);
dataSource.setUsername(postgresUsername);
dataSource.setPassword(postgresPassword);
return dataSource;
}
**\\ existing hibernate flow**
@Autowired
@Bean(name = "manager")
public HibernateTransactionManager getTransactionManager(
SessionFactory sessionFactory) {
HibernateTransactionManager transactionManager = null;
transactionManager = new HibernateTransactionManager(sessionFactory);
return transactionManager;
}
**\\included newly for JPA**
@Bean
public org.springframework.orm.jpa.JpaTransactionManager transactionManager() {
JpaTransactionManager jpaTransactionManager = new JpaTransactionManager();
jpaTransactionManager.setDataSource(getDataSource());
jpaTransactionManager
.setJpaDialect(new org.springframework.orm.jpa.vendor.HibernateJpaDialect());
return jpaTransactionManager;
}
**\\included newly for JPA**
@Bean
public EntityManager entityManger() {
return entityManagerFactory().getObject().createEntityManager();
}
\\included newly for JPA
@Bean
public LocalContainerEntityManagerFactoryBean entityManagerFactory() {
LocalContainerEntityManagerFactoryBean entityManagerFactory = new LocalContainerEntityManagerFactoryBean();
entityManagerFactory.setDataSource(getDataSource());
entityManagerFactory.setPackagesToScan(
"some package",
"some package");
Map<String, Object> jpaProperty = entityManagerFactory
.getJpaPropertyMap();
jpaProperty.put("hibernate.dialect", "org.hibernate.dialect.PostgreSQLDialect");
HibernateJpaVendorAdapter va = new HibernateJpaVendorAdapter();
va.setShowSql(Boolean.valueOf("true"));
entityManagerFactory.setJpaVendorAdapter(va);
return entityManagerFactory;
}
}
When I deployed this application i am getting below exception
org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'entityManagerFactory' defined in class ------
Caused by: java.lang.NullPointerException
at org.hibernate.hql.internal.antlr.HqlBaseParser.identPrimary(HqlBaseParser.java:4285)
at org.hibernate.hql.internal.antlr.HqlBaseParser.primaryExpression(HqlBaseParser.java:980)
at org.hibernate.hql.internal.antlr.HqlBaseParser.atom(HqlBaseParser.java:3609)
at org.hibernate.hql.internal.antlr.HqlBaseParser.unaryExpression(HqlBaseParser.java:3387)
at org.hibernate.hql.internal.antlr.HqlBaseParser.multiplyExpression(HqlBaseParser.java:3259)
at org.hibernate.hql.internal.antlr.HqlBaseParser.additiveExpression(HqlBaseParser.java:2964)
at org.hibernate.hql.internal.antlr.HqlBaseParser.concatenation(HqlBaseParser.java:597)
at org.hibernate.hql.internal.antlr.HqlBaseParser.relationalExpression(HqlBaseParser.java:2730)
at org.hibernate.hql.internal.antlr.HqlBaseParser.equalityExpression(HqlBaseParser.java:2591)
at org.hibernate.hql.internal.antlr.HqlBaseParser.negatedExpression(HqlBaseParser.java:2555)
at org.hibernate.hql.internal.antlr.HqlBaseParser.logicalAndExpression(HqlBaseParser.java:2471)
at org.hibernate.hql.internal.antlr.HqlBaseParser.logicalOrExpression(HqlBaseParser.java:2436)
at org.hibernate.hql.internal.antlr.HqlBaseParser.expression(HqlBaseParser.java:2146)
at org.hibernate.hql.internal.antlr.HqlBaseParser.exprList(HqlBaseParser.java:3994)
at org.hibernate.hql.internal.antlr.HqlBaseParser.identPrimary(HqlBaseParser.java:4278)
I would suggest another approach, which could be simpler. Make JPA leading and use the LocalContainerEntityManagerFactoryBean
to configure everything (including what you use now for hibernate). Next use the HibernateJpaSessionFactoryBean
to expose the underlying SessionFactory
.
This would save you duplicate configuration and would allow you to use a single JpaTransactionManager
for all your transactions, however you still would be able to use a SessionFactory
or HibernateTemplate
if you would.
@Configuration
@EnableJpaRepositories(basePackages = {"packagename","package name" })
@EnableTransactionManagement
public class DataBaseConfiguration {
@Autowired
private Environment env;
@Autowired
@Bean(name = "name")
public FactoryBean<SessionFactory> getSessionFactory(EntityManagerFactory emf) {
HibernateJpaSessionFactoryBean factory = new HibernateJpaSessionFactoryBean();
factory.setEntityManagerFactory(emf);
return factory;
}
**\\ existing hibernate flow**
@Bean(name = "name")
public DataSource getDataSource() {
BasicDataSource dataSource = new BasicDataSource();
dataSource.setDriverClassName(env.getRequiredProperty("postgres.driver"));
dataSource.setUrl(env.getRequiredProperty("postgres.url);
dataSource.setUsername(env.getRequiredProperty("postgres.username");
dataSource.setPassword(env.getRequiredProperty("postgres.password");
return dataSource;
}
@Bean
public JpaTransactionManager transactionManager() {
JpaTransactionManager jpaTransactionManager = new JpaTransactionManager();
jpaTransactionManager.setDataSource(getDataSource());
jpaTransactionManager.setEntityManagerFactory(entityManagerFactory());
return jpaTransactionManager;
}
@Bean
public LocalContainerEntityManagerFactoryBean entityManagerFactory() {
LocalContainerEntityManagerFactoryBean entityManagerFactory = new LocalContainerEntityManagerFactoryBean();
entityManagerFactory.setDataSource(getDataSource());
Map<String, String> properties = new HashMap<String, String>();
properties.put("hibernate.current_session_context_class", SpringSessionContext.class.getName());
entitytManagerFactory.setJpaPropertyMap(properties);
entityManagerFactory.setPackagesToScan(
"some package",
"some package");
HibernateJpaVendorAdapter va = new HibernateJpaVendorAdapter();
va.setShowSql(env.getProperty("hibernate.show-sql", Boolean.class, true);
va.setDatabasePlatform(env.getProperty("hibernate.dialect", "org.hibernate.dialect.PostgreSQLDialect");
entityManagerFactory.setJpaVendorAdapter(va);
return entityManagerFactory;
}
}
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