Count of multiple columns from a table in mysql

Question

I have total 3 tables

tbl_projects , tbl_bug , tbl_bug_history

i need to display total of 3 counts for each projects.

1.total bug for each projects- this is from tbl_bug

2. total count of "invalid", total count of "duplicate"-- this is from bug history

Output should be in the following sample format

---

project name | total bug | invalid | duplicate |

---

project-one | 5 | 6 | 7 |

Please help me table structure is define below

CREATE TABLE IF NOT EXISTS `tbl_bug` ( 
`id` int(10) NOT NULL AUTO_INCREMENT, 
`project_id` int(10) NOT NULL, 
`bugname` varchar(250) NOT NULL, 
PRIMARY KEY (`id`) 
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=11 ; 

Dumping data for table tbl_bug

INSERT INTO `tbl_bug` (`id`, `project_id`, `bugname`) VALUES 
(1, 1, 'first-bug'), 
(2, 1, 'second-bug'), 
(3, 1, 'bug-third'), 
(4, 1, 'bug-four'), 
(5, 1, 'bug-give'), 
(6, 1, 'master-bug'), 
(7, 2, 'error-notice'), 
(8, 3, 'invalid bug'), 
(9, 4, 'insufficinet memory'), 
(10, 4, 'hello bug'); 

CREATE TABLE IF NOT EXISTS `tbl_bug_history` ( 
`id` int(10) NOT NULL AUTO_INCREMENT, 
`bug_id` int(10) NOT NULL, 
`status` varchar(100) NOT NULL, 
PRIMARY KEY (`id`) 
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=21 ; 

Dumping data for table tbl_bug_history

INSERT INTO `tbl_bug_history` (`id`, `bug_id`, `status`) VALUES 
(2, 1, 'invalid'), 
(3, 2, 'invalid'), 
(6, 3, 'duplicate'), 
(7, 4, 'feedback'), 
(10, 5, 'duplicate'), 
(11, 6, 'duplicate'), 
(12, 6, 'invalid'), 
(13, 7, 'feedback'), 
(14, 7, 'normal'), 
(15, 8, 'duplicate'), 
(16, 8, 'normal'), 
(18, 9, 'feedback'), 
(19, 10, 'invalid'), 
(20, 10, 'feedback'); 



CREATE TABLE IF NOT EXISTS `tbl_projects` ( 
`id` int(11) NOT NULL AUTO_INCREMENT, 
`projectname` varchar(250) NOT NULL, 
PRIMARY KEY (`id`) 
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=5 ; 

Dumping data for table tbl_projects

INSERT INTO `tbl_projects` (`id`, `projectname`) VALUES 
(1, 'project-one'), 
(2, 'project-two'), 
(3, 'project-three'), 
(4, 'project-four');

Answer 1

Try this.This is your expected output I think.

http://sqlfiddle.com/#!2/1d756/3