Error in Sending Form file with form using AJAX
Question
I am trying to submit form using AJAX that contains CSV File. So the idea is sending the form using ajax, process it in different file by generating a table and call back the processed table back into the page.
What i Have is this,
<form id="uploadXls" action="" method="post" enctype="multipart/form-data">
<input id="uploaderFile" type="file" class="file"><br/>
<button type="button" class="btn btn-orange pull-right" name="btnSubmit" id="btnSubmit"><i class="fa fa-download"></i> SHOW FILE CONTENT</button>
</form>
and the JavaScript is,
$("#btnSubmit").click(function(){
$.ajax({
type: 'POST',
url: '../../content/maindiv_content/drawing/divpages/process_xls_file.php',
data: new FormData(this),
contentType: false,
cache: false,
processData: false,
success: function (response, textStatus, jqXHR) {
$("#showFileContentTable").html(data);
}
});
});
and im getting this kind of error in firebug,
TypeError: Argument 1 of FormData.constructor does not implement interface HTMLFormElement.
http://infserver/WeltesTankage/dist/js/jquery-1.10.2.min.js line 4 > eval
Line 14
What am i doing wrong here ? Please help me
5 answers
solution1
39 ACCPTED 2015-03-05 08:12:48
Don't pass the files into the constructor, but use append, like:
var formData = new FormData();
formData.append('file', $('input[type=file]')[0].files[0]);
data: formData
solution2
33 2015-10-05 18:55:44
You can use this approach too.
var form = $('form').get(0);
this code returns a jQuery object( $('form') ) and pass a HTML element to FormData ( get(0) ).
then in ajax request: data: new FormData(form),
solution3
3 2015-03-05 08:14:04
You pass this to the FormData constructor. In this context, this is the button clicked, identified in the error message as a HTMLFormElement .
According to the documentation the FormData constructor expects a form element. So you have to change your code accordingly:
var form = $("#uploadXls");
$ajax({
...
data: new FormData(form),
....
});
solution4
2 2016-11-23 07:33:11
may be this page help you..:)
<!DOCTYPE html>
<html>
<head>
<script src="https://code.jquery.com/jquery-3.1.1.min.js" integrity="sha256-hVVnYaiADRTO2PzUGmuLJr8BLUSjGIZsDYGmIJLv2b8=" crossorigin="anonymous">
</script>
</head>
<body>
<form method="post" id="fileinfo" enctype="multipart/form-data">
file <input type="file" name="slug"><br>
<input type="button" id="uploadBTN" value="Stash the file!"></input>
</form>
<script type="text/javascript">
$(document).ready(function()
{
$('#uploadBTN').on('click', function()
{
var form = $('form').get(0);
console.log(form);
var fd = new FormData(form);
fd.append('user_id',4);
fd.append('user_media_category_id',1);
//console.log(fd);
fd.append("user_", "This is some extra data");
$.ajax({
url: 'http://localhost/yii2/voila/project/api/web/v1/user-media/new',
type: 'POST',
data: fd,
success:function(data){
console.log(data);
},
error:function(data){
console.log(data);
},
cache: false,
contentType: false,
processData: false
});
});
});
</script>
</body>
</html>
solution5
0 2018-06-06 04:52:23
Try this form, it works for me without problems, Greetings, I hope I can help you.
//normalize form
var formulario = new FormData($('#form_img').get(0));
formulario.append('file', $('#customFile')[0].files[0]);
//AND add in Ajax call
data:formulario
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