C - Casting char array to an integer pointer?

Question

I have the following source code and there is one line, which i cannot understand the casting is been made. Can anyone explain please? I know the casting to an integer pointer (int *) but this is different. I cannot understand what the final line does. Is it returning an integer pointer? or i am wrong?

const unsigned char sc[] =  {  0x01, 0x01, 0x01, 0x01   };
return ((int (*)(void))sc)();

Answer 1

(int (*)(void))sc takes address of an array sc and converts it to a pointer to function which returns int .

() at the end then calls this function, and return value of this function (type int ) is again returned.

Weird part is that it seems as if the intention was to call function at address 0x01010101 , but it uses the address of array sc instead, which may be an error.