I have a Play-scala v2.3 application. Looking from this guide about Json Combinators , I'm trying to do this:
object Application extends Controller {
case class Foo(id: String, docs: List[Map[String, _]])
implicit val fooReads = (
(JsPath \ "id").read[String] and
(JsPath \ "docs").read[List[Map[String, _]]]
)(Foo.apply _)
...
}
But then I got compile error:
No Json deserializer found for type List[Map[String, _]]. Try to implement an implicit Reads or Format for this type.
(JsPath \ "docs").read[List[Map[String, _]]]
^
This is the example json that need to be read:
{
"id": "001",
"docs": [
{
"name": "Billy",
"level": 2,
"marked": false
},
{
"name": "Fred",
"level": 5,
"marked": true
}
]
}
I also have tried this:
case class Foo(id: String, docs: Map[String, _])
implicit val fooReads = (
(JsPath \ "id").read[String] and
(JsPath \ "docs").read[Map[String, _]]
)(Foo.apply _)
Same error too.
It seems Play's JSON combinator doesn't work for Map
type. Anyone know how to solve this?
You'd be a lot better off avoiding Map[String, Any]
, and Scala and Play make this easy. A much better solution is to define a custom case class for the thing you're trying to represent as a map:
import play.api.libs.json._
case class Doc(name: String, level: Int, marked: Boolean)
case class Foo(id: String, docs: List[Doc])
implicit val docFormat = Json.format[Doc]
implicit val fooFormat = Json.format[Foo]
val json = Json.parse(...)
And then:
scala> json.as[Foo]
res0: Foo = Foo(001,List(Doc(Billy,2,false), Doc(Fred,5,true)))
Or if you want more control:
import play.api.libs.functional.syntax._
import play.api.libs.json._
implicit val fooReads: Reads[Foo] = (
(__ \ 'id).read[String] and
(__ \ 'docs).read(
Reads.list((
(__ \ 'name).read[String] and
(__ \ 'level).read[Int] and
(__ \ 'marked).read[Boolean]
)(Doc.apply _))
)
)(Foo.apply _)
If you really need a Map[String, Any]
, you can always write a conversion method on Doc
.
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