This program doesn't work and I don't know why.
#include <stdio.h>
int main()
{
printf("%а", 20.0);
}
I am compiling in C99. Expected output is 0x1.4p+4
The а
is CYRILLIC SMALL LETTER A (U+0430)
, but you have to use LATIN SMALL LETTER A (U+0061)
: a
.
If you're using a compiler that is able to check format strings like Clang or GCC, then compile with (at least) -Wall
which includes -Wformat
( GCC Warning documentation )
5 : warning: unknown conversion type character 0xffffffd0 in format [-Wformat]
5 : warning: too many arguments for format [-Wformat-extra-args]
Its really wired. When I copypaste your code it turns into printf("%?", 20.0);
You should check your character encoding.
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