how can i detect when a button is clicked but not released in android

Question

我正在寻找一种方法来找出如何在单击但未松开按钮时通过使用Java代码来更改android中按钮的颜色，很高兴能得到帮助。

Answer 1

button.setOnTouchListener(new View.OnTouchListener() {

    public void onTouch(View view, MotionEvent e) {
        switch(e.getAction()) {
            case MotionEvent.ACTION_DOWN:
                System.out.println(" mouse pressed ");
                break;
            case MotionEvent.ACTION_UP:
                System.out.println(" mouse released");
                break;
        }

    }
});

you can use MotionEvent.ACTION_DOWN case to handle your button color change logic.

hope this will be help to you

if you got it inform me :)

Answer 2

Check out the documentation at Android Documentation . It shows that button has different states and you can align color on each state. Also check this link

Answer 3

You can use the selector for that like below code

Create selet.xml in drawable

<?xml version="1.0" encoding="utf-8"?>
<selector xmlns:android="http://schemas.android.com/apk/res/android">
<!-- Selector style for listrow -->
<item 
 android:state_selected="false"
    android:state_pressed="false" 
    android:drawable="@drawable/gradient_bg" />
<item android:state_pressed="true" 
    android:drawable="@drawable/gradient_bg_hover" />
<item android:state_selected="true"
 android:state_pressed="false" 
    android:drawable="@drawable/gradient_bg_hover" />
</selector>

Now set the background of button like below

 <Button
        android:id="@+id/button"
        android:layout_width="match_parent"
        android:layout_height="wrap_content"
       android:background="@drawable/selector" />