I have a 8 bit byte that represents the states of 8 physical switches. I need to do something different for each permutation of switches being on and off. My first idea was to write a 256 case switch statement, but it quickly became tedious to type.
Is there a better way to do this?
Edit: I should have been a bit clearer on the functions. I have 8 buttons that each do one thing. I need to be able to detect if multiple switches are pressed at once so I can run both functions at the same time.
You can use an array of function pointers. Be careful to index it by a positive value - a char
might be signed. Whether this is any more tedious than using a switch
statement is arguable - but execution will certainly be quicker.
#include <stdio.h>
// prototypes
int func00(void);
int func01(void);
...
int funcFF(void);
// array of function pointers
int (*funcarry[256])(void) = {
func00, func01, ..., funcFF
};
// call one function
int main(void){
unsigned char switchstate = 0x01;
int res = (*funcarry[switchstate])();
printf ("Function returned %02X\n", res);
return 0;
}
// the functions
int func00(void) {
return 0x00;
}
int func01(void) {
return 0x01;
}
...
int funcFF(void) {
return 0xFF;
}
您可以定义一个函数数组,并使用字节作为数组中的索引,并在数组中的给定位置相应地调用该函数。
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