I have this piece of code, and print the output to a txt file. However whenever I open a file, f=open("out.txt",'w') it shows unexpected indent. I guess I am placing the line of code to a wrong position. Can anyone help.
if(cp<0):
print("No Common Predecessor")
elif (posa < posb):
if(posa<0):
posa=0
print("Common Predecessor: %s" %n[posa])
else:
if(posb < 0):
posb=0
print("Common Predecessor: %s" %m[posb])
In Python3 the output redirection is as simple as
print(....., file = open("filename",'w'))
Refer the docs
In your particular case you can even use the with open
syntax as in
if(cp<0):
print("No Common Predecessor")
elif (posa < posb):
if(posa<0):
posa=0
with open('out.txt','w')as f:
print("Common Predecessor: %s" %n[posa])
f.write("Common Predecessor: %s" %n[posa])
else:
if(posb < 0):
posb=0
with open('anotherout.txt','w')as f:
print("Common Predecessor: %s" %m[posb])
f.write("Common Predecessor: %s" %m[posb])
Note - It is always better to use 'a'
(append) instead of 'w'
incase you are re-executing the program.
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