If I had the following code
attributes = []
attributes.append({'attribute': 'noir', 'group': 'coloris', 'id': '8'})
attributes.append({'attribute': 's', 'group': 'taille_textile', 'id': '29'})
attributes.append({'attribute': 'm', 'group': 'taille_textile', 'id': '24'})
attributes.append({'attribute': 'l', 'group': 'taille_textile', 'id': '25'})
attributes.append({'attribute': 'xl', 'group': 'taille_textile', 'id': '26'})
and I wanted to return an object of the list which contained a certain id, what would be the best way to do that?
I know that one solution would be to use the for
loop like this
def getItemById(id):
for i in attributes:
for k,v in i.items():
if (k == 'id' and v == id):
return i
I'm sure there must be a much more elegant or efficient way to do it other than this?
Is there an opportunity to use lambdas here? would that give a performance benefit?
你可以使用一个发电机:
next(attr for attr in attributes if attr['id'] == id_to_find)
For example, you want to return object with 'id'='29'
This works
[x for x in attributes if x['id']=='29'][0]
{'attribute': 's', 'group': 'taille_textile', 'id': '29'}
Another approach is to convert List to a pandas DataFrame.
import pandas as pd
df = pd.DataFrame(attributes)
#get all columns where id=8
print df[df['id']=='8']
#get specific column where id=29
print df['attribute'][df['id']=='29']
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