Pandas indexing by both boolean `loc` and subsequent `iloc`

Question

I want to index a Pandas dataframe using a boolean mask, then set a value in a subset of the filtered dataframe based on an integer index, and have this value reflected in the dataframe. That is, I would be happy if this worked on a view of the dataframe.

Example:

In [293]:

df = pd.DataFrame({'a': [0, 1, 2, 3, 4, 5, 6, 7],
                   'b': [5, 5, 2, 2, 5, 5, 2, 2],
                   'c': [0, 0, 0, 0, 0, 0, 0, 0]})

mask = (df['a'] < 7) & (df['b'] == 2)
df.loc[mask, 'c']

Out[293]:
2    0
3    0
6    0
Name: c, dtype: int64

Now I would like to set the values of the first two elements returned in the filtered dataframe. Chaining an iloc onto the loc call above works to index:

In [294]:

df.loc[mask, 'c'].iloc[0: 2]

Out[294]:

2    0
3    0
Name: c, dtype: int64

But not to assign:

In [295]:

df.loc[mask, 'c'].iloc[0: 2] = 1

print(df)

   a  b  c
0  0  5  0
1  1  5  0
2  2  2  0
3  3  2  0
4  4  5  0
5  5  5  0
6  6  2  0
7  7  2  0

Making the assign value the same length as the slice (ie = [1, 1] ) also doesn't work. Is there a way to assign these values?

Answer 1

This does work but is a little ugly, basically we use the index generated from the mask and make an additional call to loc :

In [57]:

df.loc[df.loc[mask,'c'].iloc[0:2].index, 'c'] = 1
df
Out[57]:
   a  b  c
0  0  5  0
1  1  5  0
2  2  2  1
3  3  2  1
4  4  5  0
5  5  5  0
6  6  2  0
7  7  2  0

So breaking the above down:

In [60]:
# take the index from the mask and iloc
df.loc[mask, 'c'].iloc[0: 2]
Out[60]:
2    0
3    0
Name: c, dtype: int64
In [61]:
# call loc using this index, we can now use this to select column 'c' and set the value
df.loc[df.loc[mask,'c'].iloc[0:2].index]
Out[61]:
   a  b  c
2  2  2  0
3  3  2  0

Answer 2

How about.

ix = df.index[mask][:2]
df.loc[ix, 'c'] = 1

Same idea as EdChum but more elegant as suggested in the comment.

EDIT: Have to be a little bit careful with this one as it may give unwanted results with a non-unique index, since there could be multiple rows indexed by either of the label in ix above. If the index is non-unique and you only want the first 2 (or n) rows that satisfy the boolean key, it would be safer to use .iloc with integer indexing with something like

ix = np.where(mask)[0][:2]
df.iloc[ix, 'c'] = 1

Answer 3

I don't know if this is any more elegant, but it's a little different:

mask = mask & (mask.cumsum() < 3)

df.loc[mask, 'c'] = 1

   a  b  c
0  0  5  0
1  1  5  0
2  2  2  1
3  3  2  1
4  4  5  0
5  5  5  0
6  6  2  0
7  7  2  0