Call Javascript function in PHP

Question

I need to call a javascript function and use the results(Json) as variable for PHP. I have the following function:

 <script type="text/javascript" src="Scripts/jquery-1.9.1.min.js"></script> <script> $(function () { var baseUrl = 'https://XXXXXXXXX/'; var uid = 'XXXX'; var pwd = 'XXXX'; GetProd('DT.X0CEB.009', '1'); function GetProd(cod_prod, qtd) { jQuery.support.cors = true; $.ajax({ url: baseUrl + 'api/Prod?ref=' + encodeURIComponent(cod_prod) + '&qtd=' + qtd, type: 'GET', jsonp: "callback", dataType: 'jsonp', username: uid, password: pwd, success: function (data, textStatus, xhr) { document.write(data); }, error: function (xhr, textStatus, errorThrown) { alert(xhr.responseText); } }); } }); </script> 

This returns this:

Object { Ref: "DT.X0CEB.009", Desc: "Monitor UltraHD P2715Q 68.6cm 27"", State: 0, Price: Object, Tax: Object, Stock: 2, Availability: null }

Can anybody help me how to use this fields (ref, desc, state, ...)in php? Regards Pedro

Answer 1

You are sending them as GET params therefore they should be available in your endpoint via $_GET. You could also try sending a data object via POST and retrieve them with $_POST in your php API.

$.ajax({
  url: 'yourUrl',
  method: 'POST',
  data: {
    param1: param1,
    param2: param2
  },
  success: function(data) {
    //do something with data
  }
});

PHP

$param1 = $_POST['param1'];
$param2 = $_POST['param2'];