How to make a CSV file from a number of lists?

Question

I am trying to make a csv file using the lists

['2005-04-18', '2005-04-19', '2005-04-20']

['1', '1', '1']

['0.7683', '0.766664', '0.764696']

['1.380162', '1.373308', '1.358544']

with the dates in the first column and the corresponding values across the rows

i already have

with open((os.path.join('data','hist', 'rates-'+date1+' to ' +date2+ '.csv')), 'wt') as my_csv:
    csv_writer = csv.writer(my_csv, lineterminator='\n')
    csv_writer.writerow(["Date",curr1, curr2, curr3])  

which gives me the file with the headers. How can I finish this?

Answer 1

You use a loop to process the elements of the arrays that you have.

a = ['2005-04-18', '2005-04-19', '2005-04-20']
b = ['1', '1', '1']
c = ['0.7683', '0.766664', '0.764696']
d = ['1.380162', '1.373308', '1.358544']

You can use zip to create tuples from the lists and write those:

for row in zip(a, b, c, d):
    csv_writer.writerow(row)

Or you can just youse string formatting and print it into the file yourself (without using csv_writer):

for i in range(len(a)):
    csv_writer.writerow('{}, {}, {}, {}'
        .format(a[i], b[i], c[i], d[i]))