Demo: jQuery Ajax Call to PHP Script with JSON Return

Question

I've tried out this tutorial http://labs.jonsuh.com/jquery-ajax-php-json/ but it's not working and I've followed exactly as the direction goes. i think it's because of the return.php.

index.html

 <html> <head> <script src="http://code.jquery.com/jquery-1.11.0.min.js"></script> <script type="text/javascript"> $("document").ready(function(){ $(".js-ajax-php-json").submit(function(){ var data = { "action": "test" }; data = $(this).serialize() + "&" + $.param(data); $.ajax({ type: "POST", dataType: "json", url: "response.php", data: data, success: function(data) { $(".return").json( "Favorite beverage: " + data["favorite_beverage"] + "<br />Favorite restaurant: " + data["favorite_restaurant"] + "<br />Gender: " + data["gender"] + "<br />JSON: " + data["json"] ); alert("Form submitted successfully.\\nReturned json: " + data["json"]); } }); return false; }); }); </script> </head> <body> <form action="return.php" class="js-ajax-php-json" method="post" accept-charset="utf-8"> <input type="text" name="favorite_beverage" value="" placeholder="Favorite restaurant" /> <input type="text" name="favorite_restaurant" value="" placeholder="Favorite beverage" /> <select name="gender"> <option value="male">Male</option> <option value="female">Female</option> </select> <input type="submit" name="submit" value="Submit form" /> </form> <div class="return"> [HTML is replaced when successful.] </div> </body> </html>

response.php

<?php
if (is_ajax()) {
  if (isset($_POST["action"]) && !empty($_POST["action"])) { //Checks if action value exists
    $action = $_POST["action"];
    switch($action) { //Switch case for value of action
      case "test": test_function(); break;
    }
  }
}

//Function to check if the request is an AJAX request
function is_ajax() {
  return isset($_SERVER['HTTP_X_REQUESTED_WITH']) && strtolower($_SERVER['HTTP_X_REQUESTED_WITH']) == 'xmlhttprequest';
}

function test_function(){
  $return = $_POST;

  //Do what you need to do with the info. The following are some examples.
  //if ($return["favorite_beverage"] == ""){
  //  $return["favorite_beverage"] = "Coke";
  //}
  //$return["favorite_restaurant"] = "McDonald's";

  $return["json"] = json_encode($return);
  echo json_encode($return);
}
?>

Answer 1

This is how your html has to look like...

HTML:

    <html>
    <head>
    <script src="http://code.jquery.com/jquery-1.11.0.min.js"></script>
    <script type="text/javascript">
    $("document").ready(function(){
      $(".js-ajax-php-json").submit(function(){
        var data = {
          "action": "test"
        };
        data = $(this).serialize() + "&" + $.param(data);
        $.ajax({
          type: "POST",
          dataType: "json",
          url: "response.php", 
          data: data,
          success: function(data) {
            $(".return").html(
              "Favorite beverage: " + data["favorite_beverage"] + "<br />Favorite restaurant: " + data["favorite_restaurant"] + "<br />Gender: " + data["gender"] + "<br />JSON: " + data["json"]
            );

            alert("Form submitted successfully.\nReturned json: " + data["json"]);
          }
        });
        return false;
      });
    });
    </script>
    </head>
    <body>
    <form action="return.php" class="js-ajax-php-json" method="post" accept-charset="utf-8">
      <input type="text" name="favorite_beverage" value="" placeholder="Favorite restaurant" />
      <input type="text" name="favorite_restaurant" value="" placeholder="Favorite beverage" />
      <select name="gender">
        <option value="male">Male</option>
        <option value="female">Female</option>
      </select>
      <input type="submit" name="submit" value="Submit form"  />
    </form>

    <div class="return">
      [HTML is replaced when successful.]
    </div>
    </body>
    </html>

PHP stays untouched as response.php

the magic change is

    $(".return").json(....)

in success callback to

    $(".return").html(....)

Demo: jQuery Ajax Call to PHP Script with JSON Return

Question

1 answers

solution1
2 2015-05-04 19:00:43

Demo: jQuery Ajax Call to PHP Script with JSON Return

Question

1 answers

solution1 2 2015-05-04 19:00:43

solution1
2 2015-05-04 19:00:43