How to pass data to another page using jquery ajax
Question
I have a problem on ajax call.
Here is my code regarding the ajax:
$('#Subjects').click(function() {
$.ajax({
type: 'POST',
url: '../portal/curriculum.php',
data: 'studentNumber='+$('#StudentID').val(),
success: function(data)
{
$('#curriculum').html(data);
}
});
});
When I echo studentNumber on another page, the studentNumber is undefined . Why is that?
5 answers
solution1
3 2015-05-19 10:19:40
Simply modify your code like this:
JS
$('#Subjects').click(function() {
$.ajax({
type: 'POST',
url: '../portal/curriculum.php',
data: { studentNumber: $('#StudentID').val() },
success: function(data)
{
$('#curriculum').html(data);
}
});
});
PHP
<?php
$var = $_POST['studentNumber'];
?>
If you still can not make it works.. other things you should consider..
url: '../portal/curriculum.php',
1) Please use full URL http://yourdomain.com/portal/curriculum.php or absolute path like /portal/curriculum.php
2) Add an error callback to check out the error message
$('#Subjects').click(function() {
$.ajax({
type: 'POST',
url: '../portal/curriculum.php',
data: { studentNumber: $('#StudentID').val() },
success: function(data)
{
$('#curriculum').html(data);
},
error: function (xhr, ajaxOptions, thrownError) {
alert(xhr.status);
alert(thrownError);
}
});
});
solution2
1 2015-05-19 09:57:54
<!DOCTYPE html>
<html>
<head>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.11.2/jquery.min.js"></script>
<script>
$(document).ready(function(){
$("button").click(function(){
$.post("test1.php",
{
name: "Makemelive Technologies",
city: "Mumbai"
},
function(data,status){
alert("Data: " + data + "\nStatus: " + status);
});
});
});
</script>
</head>
<body>
<button>Send an HTTP POST request to a page and get the result back</button>
</body>
</html>
The above will make a call to test1.php and its code will be
<?php
$fname=$_REQUEST['name'];
$city= $_REQUEST['city'];
echo "Company Name is ". $fname. " and it's located in ". $city ;
?>
solution3
1 2015-05-19 11:55:49
$('#Subjects').click(function() {
$.ajax({
type: 'POST',
url: '../portal/curriculum.php',
data: { studentNumber: $('#StudentID').val() },
success: function(data)
{
//here data is means the out put from the php file it is not $('#StudentID').val()
$('#curriculum').html(data);
}
});
});
as exsample if you echo some text on php it will return with data $('#curriculum').html(data);
try to change
//change
success: function(data)
{
$('#curriculum').html(data);
//to
success: function(result)
{
$('#curriculum').html(result);
check what will happen. post us php file too curriculum.php
solution4
0 2019-05-11 06:39:54
You can use through Jquery,Ajax and php
step 1. index.php
<div id="div_body_users">
</div>
<form method="post" id="frm_data" action="">
<input type="button" id="target" name="submit" value="submit">
<input type="key" id="key" name="key" value="1234">
</form>
<script src="https://code.jquery.com/jquery-2.2.4.min.js"></script>
<script>
$(document).ready(function(){
$( "#target" ).click(function() {
// alert("test");
var frm_mail = document.getElementById("frm_data");
var frm_mail_data = new FormData(frm_mail);
$.ajax({
url: "http://localhost/test.php",
data: frm_mail_data,
cache: false,
processData: false,
contentType: false,
type: 'POST',
success: function (result) {
document.getElementById('div_body_users').innerHTML=result;
}
});
});
});
</script>
step 2. create test.php
<?PHP
//print_r($_POST);
if($_POST['key']=='1234'){
echo "success";
exit(0);
}
?>
solution5
-3 2016-02-15 10:11:23
$.ajax({
type: "GET",
url: "view/logintmp.php?username="+username+"&password="+password,
}).done(function( msg ) {
var retval = printmsgs(msg,'error_success_msgs');
if(retval==1){
window.location.href='./';
}
});
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