How to access web.xml init parameters in JSP
Question
I have stated my init parameter in web.xml and on accessing same in init.jsp I get output as null . I am using Tomcat-8
My web.xml is:
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://xmlns.jcp.org/xml/ns/javaee" xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javaee http://xmlns.jcp.org/xml/ns/javaee/web-app_3_1.xsd" id="WebApp_ID" version="3.1">
<display-name>SecondWebProject</display-name>
<welcome-file-list>
<welcome-file>index.html</welcome-file>
</welcome-file-list>
<servlet>
<servlet-name>InitJsp</servlet-name>
<jsp-file>/init.jsp</jsp-file>
<init-param>
<param-name>default_username</param-name>
<param-value>default user</param-value>
</init-param>
</servlet>
<servlet-mapping>
<servlet-name>InitJsp</servlet-name>
<url-pattern>/init.jsp</url-pattern>
</servlet-mapping>
</web-app>
MY init.jsp is:
<%@ page language="java" contentType="text/html; charset=UTF-8"
pageEncoding="UTF-8"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"
"http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title>Init jsp</title>
</head>
<body>
Default username is: <%= config.getInitParameter("default_username") %>
<br>
Default username is: <%=
getServletConfig().getInitParameter("default_username") %>
</body>
</html>
File structure within Eclipse is as:
I am not able to find where I am doing wrong. Any help from your side will be valuable..
1 answers
solution1
0 ACCPTED 2015-05-24 07:58:15
I tested ur code(with tomcat7) & it is running fine, Only if i Put my jsp at correct path, path which is mentioned in 提到的路径）时
Check snapshot for reference, if place jsp directly under
Check the directory structure
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