Each row in my tableview have a postID. And I want to get this id and send to another View.
How can I do that?
override func tableView(tableView: UITableView, cellForRowAtIndexPath indexPath: NSIndexPath) -> UITableViewCell {
let cell = tableView.dequeueReusableCellWithIdentifier("Cell", forIndexPath: indexPath) as! PostsTableViewCell
//get posts data
var rowData: NSDictionary = Posts[indexPath.row] as! NSDictionary
//get title
let title:String = rowData["post_title"] as! String
cell.posttitle.text = title
//get categorty
let category:String = rowData["category_name"] as! String
cell.postcategory.text = category
//get image
let imgurl = rowData["post_feature_image"] as! String
let realurl = root + imgurl
var imgURL: NSURL = NSURL(string: realurl)!
let imgData = NSData(contentsOfURL: imgURL)
cell.fimg.image = UIImage(data: imgData!)
// get post iD
var postID:String = rowData["post_id"] as! String
return cell
}
override func tableView(tableView: UITableView, didSelectRowAtIndexPath indexPath: NSIndexPath) {
let ccell = tableView.cellForRowAtIndexPath(indexPath)
let cid:String = ccell?.contentMode.rawValue(String: postID)
}
Use the data model, not the cell
override func tableView(tableView: UITableView, didSelectRowAtIndexPath indexPath: NSIndexPath) {
var rowData: NSDictionary = Posts[indexPath.row] as! NSDictionary
let cid:String = rowData["post_id"] as! String
}
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.