Is object std::shared_ptr findable by its std::weak_ptr?

Question

So I have a std::vector<std::shared_ptr<T>> myListOfT; and I have a std::weak_ptr<T> ptrToOneT; that was created from one of the pointers used to fill that container (say I have it inside a callback function). Will std::find on that container and my weak_ptr give me an iterator to the original shared_ptr (if such one exists in the collection)? Is it guaranteed somewhere in standard or is this implementation dependent?

Answer 1

We can get away without locking the weak_ptr by using std::weak_ptr::owner_before . I'll use a slightly more verbose solution than necessary and introduce owner_equal , which is the counterpart to std::owner_less :

template<typename T>
class owner_equal
{
private:
    template<typename L, typename R>
    static bool e(L const& l, R const& r)
    { return !(l.owner_before(r)) && !(r.owner_before(l)); }

public:
    using S = std::shared_ptr<T>;
    using W = std::weak_ptr<T>;

    bool operator()(S const& l, W const& r) const { return e(l, r); }
    bool operator()(W const& l, S const& r) const { return e(l, r); }
};

With this function object type, we can customize std::find_if :

using T = int;
std::vector<std::shared_ptr<T>> myListOfT =
  {std::make_shared<int>(0), std::make_shared<int>(1), std::make_shared<int>(2)};

int const pos = 1;
std::weak_ptr<T> ptrToOneT = myListOfT[pos];

auto pred = [&ptrToOneT](std::shared_ptr<T> const& e)
            { return owner_equal<T>{}(e, ptrToOneT); };

auto const r = std::find_if(begin(myListOfT), end(myListOfT), pred);
assert(r - begin(myListOfT) == pos);

The lambda can be replaced by a bind-expression such as:

auto pred = std::bind(owner_equal<T>{}, std::cref(ptrToOneT),
                      std::placeholders::_1);

---

@davidhigh suggested an optimization:

template<typename FwdIt, typename T>
FwdIt findWeakPtr(FwdIt b, FwdIt e, std::weak_ptr<T> const& w)
{
    if(w.expired()) return e;
    else
    {
        auto pred = [&w](std::shared_ptr<T> const& e)
                    { return owner_equal<T>{}(e, w); };
        return std::find_if(b, e, pred);
    }
}

(not tested)

This also slightly changes the behaviour: If the weak_ptr is "empty", eg having been created from an empty shared_ptr or via the default ctor, it will compare equal to any empty shared_ptr via owner_equal . However, weak_ptr::expired is true in that case. Therefore, the optimized version will not find empty shared pointers in the range.

---

Should empty shared pointers be found in the range?

Consider:

using T = int;
std::vector<std::shared_ptr<T>> myListOfT =
  {std::shared_ptr<T>(), std::shared_ptr<T>()};

int const pos = 1;
std::weak_ptr<T> ptrToOneT = myListOfT[pos];

auto const r = my_weak_ptr_find(begin(myListOfT), end(myListOfT), ptrToOneT);
auto const r_pos = r - begin(myListOfT);

Empty shared pointers are equal . Therefore, if you allow finding empty shared pointers, r_pos != pos && r != end(myListOfT) is possible. For example, the first version of the algorithm in this answer yields r_pos == 0 .

---

For additional context, see:

• N1590 - Smart Pointer Comparison Operators
• Equality-compare std::weak_ptr

Answer 2

std::weak_ptr::lock() is how you "promote" a weak_ptr to a shared_ptr :

std::weak_ptr<T> ptrToOneT;
auto observe = ptrToOneT.lock();
if (observe) {
    // observe now shares ownership of the one T
}
else {
    // there is no managed object or it has already
    // been destroyed
}

If lock() succeeds, then you have a normal std::shared_ptr<T> that you can use to find() like you would any other object in a container. Though you may not need to find() it since you already have it (unless you want to erase() it or something).

Side-note, with shared_ptr , it's not really meaningful to refer to the "original shared_ptr "

Answer 3

I had a similar problem a few days ago in my own code. According to my SO-research, it is possible to do what you asked for. Lock the weak-pointer and if the shared-pointer is not-expired, then use std::find

struct A{};

int main()
{
    std::vector<std::shared_ptr<A> > sptr_vec;
    std::weak_ptr<A> wptr;

    if(auto sptr = wptr.lock())
    {
        auto it = std::find(std::begin(sptr_vec), std::end(sptr_vec), sptr);
        if (it != std::end(sptr_vec))
        {
            std::cout<<"found"<<std::endl;
        }
    }
}

Note that the C++ standard itself is not that relevant here -- the heart of the comparison of the shared-pointers is a comparison of the contained raw pointers, ie addresses in memory are compared.

Alternatively, if you have a vector of weak-pointers, you could use std::find_if with a predicate that locks on the fly:

    std::vector<std::weak_ptr<A> > wptr_vec;
    std::shared_ptr<A> sptr;

    auto it = std::find_if(std::begin(wptr_vec), std::end(wptr_vec)
                         , [&sptr](auto const& w){ auto s = w.lock();
                                                   if (s) {return s == sptr;}
                                                   return false; });
    if (it != std::end(wptr_vec))
    {
        std::cout<<"found"<<std::endl;
    }

Note that fot this application, I would consider the equivalence of nullptr with itself, ie that nullptr == nullptr is true , as unwanted. Thus I excluded this case from the predicate (and also from the search in the first code block).

EDIT: just considered the owner_lock solution by @dyp, which is advantageous if it is just about the search.