I have an XML file with code:
<?xml version="1.0" encoding="utf-8"?>
<car_ads>
<car_make make="suzuki" adj_kw="null">
<model data_type="string"adj_kw="null" class="کار_ماڈل ">
<model_instance>ALTO</model_instance>
<model_instance>KHYBER</model_instance>
</model>
<year data_type="integer" adj_kw="yes" class="ایر ">
<adj_kw>ماڈل </adj_kw>
<adj_kw>ء</adj_kw>
</year>
<price data_type="string" adj_kw="yes" class=" قیمت " >
<adj_kw>قیمت </adj_kw>
<adj_kw>ڈیمانڈ </adj_kw>
</price>
</car_make>
<car_make make="سوزوکی" adj_kw="null">
<model data_type="string" adj_kw="null" class="کار_ماڈل ">
<model_instance>alto</model_instance>
<model_instance>آلٹو</model_instance>
</model>
<year data_type="integer" adj_kw="yes" class="ایر ">
<adj_kw>ماڈل </adj_kw>
<adj_kw>ء</adj_kw>
<adj_kw>ایئرآفمینوفیکچرنگ </adj_kw>
</year>
<price data_type="string" adj_kw="yes" class=" قیمت " >
<adj_kw>قیمت </adj_kw>
<adj_kw>ڈیمانڈ </adj_kw>
</price>
</car_make>
</car_ads>
I am parsing this using XmlDocument in c#
string xmlText = File.ReadAllText(@"G:\\car_xml_final.xml");
var doc = new XmlDocument();
doc.LoadXml(xmlText);
If I know attribute value (egin my example attribute class =" ایر") I want to get its corresponding element name (ie element= "year").
Thanks @Charles Mager for pointing out the difference between XmlDocument
and XDocument
. If you use XDocument
, you can use either LINQ:
var element = doc.Root.Descendants().FirstOrDefault(e => e.Attribute("class") == " ایر");
var elementName = element.Name;
or XPath:
var element = doc.XPathSelectElement("//[@class=' ایر']");
var elementName = element.Name;
to get your desired result.
If you stick to XmlDocument
, there's the SelectSingleNode
method:
var element = doc.DocumentElement.SelectSingleNode("descendant::[class=""' ایر'""]");
As mentioned in the other answer, you can use SelectSingleNode()
or SelectNodes()
to get sepcific element(s) from XmlDocument
passing an XPath expression as parameter, for example :
var result = doc.SelectNodes("//*[@class='ایر ']");
foreach (XmlNode node in result)
{
//print element name
Console.WriteLine(node.Name);
}
brief explanation about XPath being used :
//*
: select all elements regardless of the name ( *
), anywhere in the XML document ( //
)... [@class='some_class_here']
: ...having class attribute value equals certain class name
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