Soup.select, get only first result back

Question

Is there any way to just get the first result back from for i soup.select(table) ? I just want the first table, every table after it should be ignored. The code is followed by an if statement: if i.find('th', text = 'Foo'):

TLDR;

Looking for something like this: if i[0].find('th', text = 'Foo'):

Answer 1

One way is to break right after the first iteration:

for i in soup.select('table'):
    if i.find('th', text = 'Foo'):
        ...
    break

Another one is to chain methods, and catch exception if element not found:

try:
    el = soup.select('table')[0].find('th', text='Foo')
except AttributeError, TypeError:
    print('element not found')

Note: soup.select('table')[0] and soup.find('table') give the same result