Search in DBF and update record

Question

Code:

#!/usr/bin/python
db = dbf.Dbf("MEST2.DBF")
#LINE TO UPDATE:
rec = db[0]
#PROEST IS A field of my dbf. I'm assigning 1 to this field line 0
rec["PROEST"] = 1
rec.store()
del rec
db.close()

IMAGE OF DBF TABLE: http://i.stack.imgur.com/1UHE1.jpg

My problem is I can not change the records by rows, cause the position of the products (PROCOD) may vary.

Any suggestions to get the PROCOD and change the value of PROEST?

UPDATED:

#!/usr/bin/python

import dbf
db = dbf.Table('MEST2.DBF')
with db:
    procod_idx = db.create_index(lambda rec: (rec.codigo, rec.procod))
    match = procod_idx.search(match='000001')

    # should only be one product with that code
    record = match[0]   
    with record:
        record.proest = 23

But the question now is, how i edit the value based on the CODIGO field (Stock code). I have multiples stocks ID: (1, 2, 5, 11). The code update just the first result, i need update a specific record based in the CODIGO FIELD.

In SQL would be: "UPDATE PROEST SET 32 where CODIGO=11"... or CODIGO=2

SOLVED by Ethan Furman

#!/usr/bin/python

import dbf
db = dbf.Table('MEST2.DBF')
with db:
    procod_idx = db.create_index(lambda rec: (rec.codigo, rec.procod))
    match = procod_idx.search(match=(11, '000001'))
    record = match[0]
    with record:
        record.proest = 25
        record.dt_atualiz = '14/07/15 16:52'

Answer 1

You don't say which dbf package you are using, but it looks like mine .

What you want to do is create an temporary index on the PROCOD field and then you can search on it and update whichever other fields you need to:

# untested
import dbf
db = dbf.Table('MEST2.DBF')
with db:
    procod_idx = db.create_index(lambda rec: rec.procod)
    # get a list of all matching records
    match = procod_idx.search(match='000001')
    # should only be one product with that code
    record = match[0]
    with record:
        record.proest = ...
        record.dt_atualiz = ...

If the product code is not unique, then the above "should only be one product with that code comment" is wrong.

Change the index to:

procod_idx = db.create_index(lambda rec: (rec.codigo, rec.procod))

and then search with:

    match = procod_idx.search(match=(11, '000001'))
    record = match[0]
    ...
    match = procod_idx.search(match=(2, '000001'))
    record = match[0]
    ...