How to count 365 days from current system date to past and future date and fetch the data accordingly using php and mysql

Question

I want to fetch data according to date which is expired.

I have database like this

Equipment Purchase Date Expiry Date

Laptop 2015-07-15 2016-07-15
Mobile 2012-07-15 2013-07-15
Desktop 2011-07-15 2012-07-15

Now I want to fetch data which is expired, if the purchase date lies under 365 days from current date that means Equipment not expired, else expired. So, How to fetch data data which is expired and How to fetch data data which is not expired.

I managed to count date and print the condition like this.

 $purchasedate = strtotime ($row['purchasedate']);
 $todayDate = strtotime (date("j-m-Y"));
 $timeDiff = abs($todayDate - $supplydate1);
 $numberDays = $timeDiff/86400;
 $numberDays = intval($numberDays);

 if ($numberDays > 365)
 {
     $expiry = 'Warranty Expired';
 } else {

     $expiry = 'Under Warranty';
     } 

But i only want to fetch data which is expired, and which is not expired.

Please help, Thanks.

Answer 1

Use MySQL date arithmetic.

SELECT equipment,
       CASE WHEN expiryDate > CURDATE() THEN 'Current'
                                         ELSE 'Expired' END
  FROM table 

If you want to display only the expired rows, append this WHERE clause to your query.

 WHERE expiryDate <= CURDATE()

There are all sorts of cool things you can do with date arithmetic. For example, to find all the rows expiring between now and two months from now, use this WHERE clause.

WHERE expiryDate > CURDATE()
  AND expiryDate <= CURDATE() + INTERVAL 2 MONTH

Similarly, if you want to see rows where the purchase date is a year ago or more, you can do this.

WHERE purchaseDate <= CURDATE() 1 INTERVAL 1 YEAR

This SQL data arithmetic allows you to escape the need to count days or months; it knows the necessary calendar details.