Python : tuple inside tuple get child index

Question

i have this tuple:

STATUS = ((1, 'Standby'), (2, 'Approved'), (3, 'Rejected'))

The problem seems to be that this is a tuple (x,x,x) inside other tuple where x is (i,'string') . I need to get a index from the child tuple this is possible by doing this STATUS[0].index('Standby')

but this is not a good solution because i can't find directly by name.

So, i want to find the index directy without to mention what is the position of the tuple that i'm seeking.

Answer 1

Why not use a list and then use index?

STATUS = [None, 'Standby', 'Approved', 'Rejected']
STATUS.index('Standby')

returns 1

Answer 2

Well,

it seems that doesn't exist any solution by default. So you need to do a function. Using the suggestion of @tobias_k i made this possible solution.

def deepindex(mytuple,myvalue):
   for i in mytuple:
      if i.index(myvalue):
         return i.index(myvalue)

>>> deepindex(STATUS,'Standby')
>>> 1

Please if you find a better solution let me know. Thanks ;)

Answer 3

Zip and map seems to be a good approach

zip: aggregates elements from each of the iterables (*STATUS) (see docs )

map: to every item of iterable and return a list of the results (see docs )

Using this two functions: you can get the index of a tuple inside another tuple as is described on this question as STATUS.

>>> a,b= map(list,zip(*STATUS))
>>> a[b.index('Standby')]
>>> 1