Infinite 'for' loop with Bash

Question

I have a script like

#!/bin/bash
for i in {1..xx};do break="$i"
If....; then Some command
else break;fi
done

I need something which can repeat this script n times with incrementing $i.

I tried this:

For (( ; ; )); do  i=1 && echo $i && ((i++));done

But this always shows 1, not an incrementing number. I also tried $((i+=1)) .

Where xx is must be endless number.

Where break="$i" gives me how many times repeated script.

Answer 1

Using for to create an endless loop is unidiomatic, but not hard. Just make the ending condition never true; or, trivially, omit it.

for((i=0; ;++i)); do
    echo "$i"
done

The above is Bash only. The usual solution, which works in POSIX sh too, is to use while true (but then that doesn't come with an incrementing index, if that's really what you need).