MYSQL: Using DAYNAME() to get data for the nearest date to today

Question

In my mySQL db, I have a column called 'day'. Each training session has a different day - for this example, U12s has one on Tuesday and Thursday. What I want, is to get the data for the closest session (right now, that'd be Tuesday).

SELECT * 
  FROM training 
 WHERE `day` > dayname(now()) 
   AND `group` = 'U12s' 
 ORDER by `day` 
 LIMIT 1

This brings up a result, but it is sorting 'day' alphabetically, so the result is Thursday instead of Tuesday.

I also tried

SELECT * 
  FROM training 
 WHERE `day` > dayofweek(CURDATE()) 
   AND `group` = 'U12s' 
 LIMIT 1

but that brought up no results at all.

Any suggestions?

JorgeCampos' solution & syntax error:

                 SELECT * 
              FROM training 
             WHERE `day` > dayname(now()) 
               AND `group` = 'U12s' 
             ORDER BY CASE when `day` = 'Monday' then 1
                           when `day` = 'Tuesday' then 2
                           when `day` = 'Wednesday' then 3
                           when `day` = 'Thursday' then 4
                           when `day` = 'Friday' then 5
                           when `day` = 'Saturday' then 6
                           else 7 end case
             LIMIT 1

Error: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'case LIMIT 1' at line 11

Answer 1

If your day column is the name of the days and your query is already ok but the order is wrong you just need to convert the day for a value that can be ordered as you need so:

SELECT * 
  FROM training 
 WHERE `day` > dayname(now()) 
   AND `group` = 'U12s' 
 ORDER BY CASE when `day` = 'Monday' then 1
               when `day` = 'Tuesday' then 2
               ....
               when `day` = 'Saturday' then 6
               else 7 end
 LIMIT 1