Unpacking Parameter Pack in C++

Question

I have two functions f and g . f calculates it's return value asynchronously and returns a future. Now, based on several return values of f , I want to call g , but I want to make sure that the computations of the values of f happen in parallel.

Consider the following code:

template <typename T>
std::future<T> f(T& t);

template <typename... T>
void g(T&&... t)

template <typename... T>
void call_wrapper(T&&... t) {
  auto f1 = f(t1); // How do I set the values of f1... fn
  auto f2 = f(t2);
  ...
  g(f1.get(), f2.get()....); // How do I call g
}

How can I unpack the types from the variadic template T of the call_wrapper function?

Answer 1

[Edit2: I guess i misunderstood the question, i forgot subzero wanted to return std::future s and simply thought that the only problem was the parameter pack syntax. Hopefully, using an helper function as in my first edit should work though]

You can simply do:

 template <typename... T> void call_wrapper(T&&... t) { g(f(std::forward<T>(t)).get()...); } 

Unless i misunderstood what you want to do.

Edit1: if you want to do something else, you can divide the function in two calls, like this:

template<typename... T>
void helper(T&&... t) {
  // ...
  g(std::forward<T>(t).get()...);
}

template <typename... T>
void call_wrapper(T&&... t) {
  helper(f(std::forward<T>(t))...);
}

Answer 2

Here's a quick solution storing the std::future s in a std::tuple :

template <class T, std::size_t... Idx>
void callG(T &tuple, std::index_sequence<Idx...>) {
    g(std::get<Idx>(tuple).get()...);
}

template <typename... T>
void call_wrapper(T&&... t) {
    auto results = std::make_tuple(f(std::forward<T>(t))...);
    callG(results, std::index_sequence_for<T...>{});
}

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