how to call web service from javascript (ajax)
Question
i have 1 project webservice and 1 project web asp.net i want to insert data by json(ajax) i tested file service by code behind and it good, have error with code js file WebService1:
public bool HelloWorld(student obj) {
SqlConnection cnn = new SqlConnection("Data Source=PHAMHOP-LAPTOP\\SQLEXPRESS;Initial Catalog=qlsv;Integrated Security=True");
cnn.Open();
SqlCommand cmd = new SqlCommand("insert into sinhvien(name,age) values(@name,@age)", cnn);
cmd.Parameters.AddWithValue("name", obj.name);
cmd.Parameters.AddWithValue("age", obj.age);
int row = cmd.ExecuteNonQuery();
if (row == 1){
return true;
} else {
return false;
}
}
file aspx:
<script src="Scripts/jquery-1.4.1.min.js" type="text/javascript"></script>
<script type="text/javascript">
function add() {
$.ajax({
type: "POST",
url: "http://localhost:51097/Service1.asmx/HelloWorld",
data: "{'id':'1' ,'name': 'Amit', 'age': '97'}",
contentType: "application/json; charset=utf-8",
dataType: "json",
success: function (msg) {
alert("ok");
}
});
}
</script>
<body>
<input type='Button' value='gui' OnClick='add()'/>
</body>
It does not work.
2 answers
solution1
1 2015-08-06 05:05:05
Since the returned data is not JSON contentType: "application/json; charset=utf-8", dataType: "json", is not needed and the data option does not need to be a string. Pass it as an object.
Try this
function add() {
$.ajax({
type: "POST",
url: "http://localhost:51097/Service1.asmx/HelloWorld",
contentType: "application/json; charset=utf-8",
dataType: "json",
data: {
id: 1,
name: 'Amit',
age: 97
},
success: function (msg) {
alert("ok");
}
});
}
solution2
0 2015-08-06 05:03:20
Alternatively, you could try passing the JSON as a string parameter instead of as a student and deserialising it yourself using Newtonsoft or System.Web.Script.Serialization.JavaScriptSerializer.
bool HelloWorld(string obj)
instead of
bool HelloWorld(student obj)
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.