$q.all([somevar]).then(function(data)){}; , if somevar is 'undefined' when it will be resolved?

Question

$q.all([promise]).then(function(data)){
 console.log('resolved');
}; 

assume promise is 'undefined' when it will be resolved? even promise is null or undefined , it is getting resolved,So confused about $q behavior.Please could you clarify this.

Answer 1

$q.all can, even if not documented, take plain values as well and not only promises - it will automatically convert them. So your code is equivalent to

$q.all([$q.when(promise)]).then(function(data)) {
  console.log('resolved');
};

And if promise is null , you'll get a promise that is resolved with null , which is why you will finally see [null] in your data .