Process.Start not executing command

Question

I am using ImageMagick C# tool to convert PDF to JPG by calling the executable from C#. I believe I set up the command correctly but it does not execute; it just passes through Process.Start(startInfo) without executing it. I do see the command prompt popping up but nothing happens.

string PNGPath = Path.ChangeExtension(Loan_list[f], ".png");
string PDFfile = '"' + Loan_list[f] + '"';
string PNGfile = '"' + PNGPath + '"';
string arguments = string.Format("{0} {1}", PDFfile, PNGfile);
ProcessStartInfo startInfo = new ProcessStartInfo(@"C:\Program Files\ImageMagick-6.9.2-Q16\convert.exe");
startInfo.Arguments = arguments;
Process.Start(startInfo);

I wasn't sure if it was because of the double quotes I added to each argument before hand but after commenting it out and running it again, it still skipped over. Any thoughts?

Edit: To add some clarity, I am expecting a JPG files from a PDF but I see no output file from this part of code. I ran the following in my command prompt to convert PDF to JPG

"C:\Program Files\ImageMagick-6.9.2-Q16\convert.exe" "C:\Users\rwong\Desktop\RoundPoint\1000965275\1000965275_157_Credit File_10.PDF" "C:\Users\rwong\Desktop\RoundPoint\1000965275\1000965275_157_Credit File_10.png"

I explicitly called the convert.exe for clarity sake in my code. The command works fine in command prompt but when coping the structure over to C# it doesn't do anything. I see the code step into it but it continues without an error.

Edit2: Upon request below is the code and output for a Process Exit code

string PNGPath = Path.ChangeExtension(Loan_list[f], ".png");
string PDFfile = '"' + Loan_list[f] + '"';
string PNGfile = '"' + PNGPath + '"';
try
{
    Process myprocess = null;
    string[] arguments = { PDFfile, PNGfile };
    myprocess=Process.Start(@"C:\ProgramFiles\ImageMagick6.9.2Q16\convert.exe", String.Join(" ", arguments));
    Console.WriteLine("Process exit code: {0}", myprocess.ExitCode);
}
catch (Exception ex)
{
    Console.WriteLine(ex);
}

Process exit code: 1

Answer 1

Assuming that you are right and there was a problem (rather than the process just executed very quickly and exited), you can check the return code as follows:

if (Process.Start(startInfo) == null)
{
    int lastError = Marshal.GetLastWin32Error();
}

You then go here to look up the error code:

https://msdn.microsoft.com/en-us/library/windows/desktop/ms681381(v=vs.85).aspx

Hopefully, that vendor actually sets an error code on failure (they may or may not).