简体   繁体   中英

Create new EC2 keypair on AWS with Boto3

The boto3 1.1.2 docs say that the create_key_pair command is supposed to return a dict containing the private key of the newly created keypair.

I am indeed using that version…

>>> import boto3
>>> boto3.__version__
'1.1.2'

…yet when I run create_key_pair I am instead returned a KeyPair object which does not appear to contain any information about the private key. The keypair does get created, it's just that I have no way of retrieving the private key because it is only ever available at the time of the keypair's creation . Older boto APIs apparently had a .save method on the KeyPair object to save the key to a file, but that too appears to have been removed from the API.

In boto3 1.1.2, how does one create a new EC2 keypair and retrieve its private key?

The private key is available in keypair['KeyMaterial'] :

>>> import boto3
>>> ec2 = boto3.client('ec2')
>>> keypair = ec2.create_key_pair(KeyName='foo')
>>> keypair['KeyMaterial']
'-----BEGIN RSA PRIVATE KEY-----\nMIIEpAIBAAKCA...\n-----END RSA PRIVATE KEY-----'

References:

In the new versions of boto3 (I'm using 1.4.7) change this line:

keypair['KeyMaterial']

to

keypair.key_material

Add the feature to save to local keypair file

$ cat keypair.py

import boto3

keypair_name = "python_keypair"

ec2 = boto3.client('ec2')
keypair = ec2.create_key_pair(KeyName=keypair_name)

private_key_file=open(keypair_name,"w")
private_key_file.write(response['KeyMaterial'])
private_key_file.close

now you should get the private key locally

$ cat python_keypair.pem

-----BEGIN RSA PRIVATE KEY-----
MIIEpAIBAAKCAQEA14D9GAC7zVSRr3iHUyEaIF8ol5ccWBj9InVqYnF28l10EUCz
g5OLL5Ll6WiIYvlxhcRHM5d0os2Lg5SuKi0mTktYQ7QVD8RkdoEYIVrqgBir3VMf
8jG08JRhaJs4/OQk2+WAGecjcVx6joz9yXTRT3Maaec/4qNigfYMLpSsdAoZ0hrk
....

move it to ~/.ssh and change permission to 600

The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM